Answer: Add 5 to both sides
What is the first step needed to solve 4 over 7 the whole multiplied by x minus 5 equal negative 13?
Answer- Add 5 to both sides
(4/7)x - 5 = -13
• As mentioned above, first step would be,
adding 5 to both sides
=> (4/7)x - 5 + 5 = -13 + 5
=> (4/7)x = -8
• Now, transporting 7 from L.H.S. to R.H.S
=> 4x = -8 × 7
=> 4x = -56
• Now in the same way, transporting 4 from L.H.S. to R.H.S
=> x = (-56/4)
=> x = -14
• And in this way, or taking<u> (Add 5 to both sides)</u> as our first step, we find that the value of x is -14.
<u>∴ </u><u> </u><u>x = -14</u>
Hope it helps.
Answer:
20 + 0.10t
Step-by-step explanation:
The 20 is the flat rate, the .10 is the per minuet rate meaning the answer is 20 + 0.10t. plz 5 str and thx, and brailiest.
Answer:
(-9, π/5 + (2n + 1)π)
Step-by-step explanation:
Adding any integer multiple of 2π to the direction argument will result in full-circle rotations, which are identities, so this family is equivalent to the give coordinates:
(9, π/5 + 2nπ), for any integer n
Also, multiplying the radius by -1 is a point reflection, equivalent to a half-turn rotation. Then add π to the direction for another half turn, and the result is another identity. So this too is equivalent to the given coordinates:
(-9, π/5 + (2n + 1)π), for any integer n
Answer: 0.8238
Step-by-step explanation:
Given : Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with 
and 
.
Let x denotes the scores on a certain intelligence test for children between ages 13 and 15 years.
Then, the proportion of children aged 13 to 15 years old have scores on this test above 92 will be :-
![P(x>92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]](https://tex.z-dn.net/?f=P%28x%3E92%29%3D1-P%28x%5Cleq92%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B92-106%7D%7B15%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq%20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq-0.93%29%3D1-%281-P%28z%5Cleq0.93%29%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%5Cleq%20-z%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3DP%28z%5Cleq0.93%29%3D0.8238%5C%20%5C%20%5B%5Ctext%7BBy%20using%20z-value%20table.%7D%5D)
Hence, the proportion of children aged 13 to 15 years old have scores on this test above 92 = 0.8238
