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Archy [21]
3 years ago
8

91.357 decigrams to kilograms​

Mathematics
1 answer:
andrezito [222]3 years ago
3 0

the formula for decigrams to kilograms is divide the mass value by 10,000, so the answer would be 0.0091357

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3(x-k)/w =4
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Answer:

anws: 2×a+b= 3.13

Step-by-step explanation:

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Arturiano [62]

Answer:

y=\frac{1}{2}

Step-by-step explanation:

4(y+1)= \frac{3}{1-y}

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What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

Where m is the slope of the line

∴ y=\dfrac{x}{6}-7

On Comparing we get

Slope = m = \dfrac{1}{6}

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So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

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Answer:

Step-by-step explanation:

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