This sequence be represented as a recursive equation by a1=8 and an=2a1
<u>Step-by-step explanation</u>:
- 'Recursive' refers to the repetition of a specific process in a sequence.
- The given sequence is {8,16,32,64}.
- If the value is 2 times the previous value, then an=2a(n-1)
Let a1=8,
then a2 = 2a(2-1)
⇒ a2 = 2a1
⇒ a2 = 2(8)
⇒ a2 = 16
Similarly,
For a2=16,
⇒ a3 = 2(a2)
⇒ a3 = 2(16)
⇒ a3 = 32
For a3=32,
⇒ a4 = 2(a3)
⇒ a4 = 2(32)
⇒ a4 = 64
∴ The equation is recursive as a1=8 and an=2a1 to follow the sequence.
From the system of equations, we have 3 unknowns and 3 equations. Therefore, it can be solved.
<span>3x - 2y + 2z = 30 (1)
</span><span>-x + 3y - 4z = -33 (2)
</span><span>2x - 4y + 3z = 42 (3)
We can write equation 2 x as a function of y and z and substitute the new equation to the other equations.
</span>x =3y - 4z + 33 (2)
3 (3y - 4z + 3)<span> - 2y + 2z = 30 (1)
</span>2 (3y - 4z + <span>3)</span> - 4y + 3z = 42 (3)
We simplify and solve the equations and we get values,
x = 4
y = -7
z = 2
Answer:
x=4
Step-by-step explanation:
if you do ![\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D)
you'll get that 
is 64.
Answer:
Step-by-step explanation:
to do this, u would just sub ur answer choices into the inequalities and see what is true. Keeping in mind, that ur point has to satisfy both inequalities for it to be a solution.
2x + y < 12...subbing in (3,3) 3x - 2y > 2...subbing in (3,3)
2(3) + 3 < 12 3(3) - 2(3) > 2
6 + 3 < 12 9 - 6 > 2
9 < 12....true 3 > 2....true
(3,3) lies in the solution set <==
