Tell weather the fractions are equvallent

Maggie‘s brother is 11 years younger than four times her age. The sum of their ages is 54. How old is Maggie?

lbvjy [14]

Answer:

Maggie is 13

Step-by-step explanation:

Honestly, I just kept trying ages starting from 10 because I knew it wasn't going to be less than that. Then I did whatever age, in this case 13, and multiply it by 4. Then minus 11 from that number. Then take that end number and add it to the beginning number(maggies age) and you should get 54.

Math Equation Explanation:

13*4 = 52 (Maggies Age) x 4

52-11= 41 The question stated that Maggie's brother was 11 -------------------------------------years younger than her age times 4.

41 + 13 =54 The sum of both their ages.

6 0

3 years ago

Donna sells pencils for $2 and pens $3. She sold 11 items and made $30. How many pens did she sell ?

finlep [7]

Donna sold 3 pencils and 8 pens solved using simultaneous equation

What is a simultaneous equation?

Simultaneous equation refers to related equations that are solved at the same to derive answers to the unknown variables

Let assume that X pencils were sold and Y pens were sold

The total revenue is the sum of the prices multiplied by the quantities sold.

2X+3Y=30 (equation 1)

The sum of X and Y sold is 11

X+Y=11 (equation 2)

multiply the second equation by 2

2*(X+Y=11)

2X+2Y=22 (equation 3)

subtract equation 3 from 1

(2X+3Y=30)-(2X+2Y=22)

Y=8

Substitute for Y in equation 2

X+8=11

X=11-8

X=3

Which means he sold 3 pencils and 8 pens.

Find details on simultaneous equation in the link below:

brainly.com/question/20627346

#SPJ1

4 0

2 years ago

PLEASE HELP WILL GIVE BRAINLY<br><br>(USE BAR NOTATION IF NEEDED!!!!!!<br>CONVERT TO DECIMAL

emmainna [20.7K]

Answer:

3.34 is the decimal form but the question is unclear, what is it that you need?

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

For each pair of points below, think about the line that joins them. For which pairs is the line parallel to the y-axis? Circle

gogolik [260]

Answer:

Option B.

Step-by-step explanation:

If two lines are parallel then their slopes are always same.

Following this rule we can find the slope by the given pairs of coordinates of the options.

If the slope of the line is same as the slope of y axis then the line passing through these points will be parallel to the y axis.

Slope of y - axis = ∞

Option A). Slope = $\frac{y-y'}{x-x'}$

= $\frac{24-8.5}{3.22-3.2}$

= $\frac{15.5}{0.02}$

= 775

Therefore, line passing through points (3.2, 8.5) and (3.22, 24) is not parallel to y axis.

Option B). Slope of the line passing through $(\frac{40}{3},\frac{14}{3})$ and $(\frac{40}{3},7)$ will be

= $\frac{\frac{14}{3}-7}{\frac{40}{3}-\frac{40}{3}}$

= ∞

Therefore, line passing though these points is parallel to the y axis.

Option C). Slope of the line passing through $(2.9,5.4)$ and (7.2, 5.4)

= $\frac{5.4-5.4}{7.2-2.9}$

= 0

Therefore, slope of this line is not equal to the slope of y axis.

Option B. is the answer.

5 0

3 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago