Answer:
Width of field = 50 yards
Length of Yards = 106 yards
Step-by-step explanation:
Let the width of field be x yards
given that "The length of a new rectangular playing field is 6 yards longer than double the width"
Length of Yards= 2*width of field + 6 = 2x+6 yards
perimeter of the rectangular playing field = 312 yards
We know that perimeter of rectangle is given by 2(length + width ).
Since field is rectangular then
2(length + width ) = 312
2(x+2x+6) = 312
=> 3x+6 = 312/2 = 156
=> 3x = 156 - 6 = 150
=> x = 150/3 = 50
Thus,
Width of field is x = 50 yards
Length of Yards= 2x+6 yards = 2*50+6 yards = 106 yards
9514 1404 393
Answer:
D.) a+2b
Step-by-step explanation:
The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...
A) 3(0) = 0 . . . even
B) 1 +3 = 4 . . . even
C) 2(1+0) = 2 . . . even
D) 1 +2(0) = 1 . . . odd
_____
<em>Additional comment</em>
These rules apply to even/odd:
- odd × odd = odd
- odd × even = even
- even × even = even
- odd + odd = even
- odd + even = odd
- even + even = even
Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.
Answer:
25
Step-by-step explanation:
I think it’s the first one
