What is the 6th term of the geometric sequence where a1=625 and a2=-125
1 answer:
You might be interested in
Using the binomial distribution, it is found that there is a 0.0108 = 1.08% probability of the coin landing tails up at least nine times.
<h3>What is the binomial distribution formula?</h3>The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- The coin is fair, hence p = 0.5.
- The coin is tossed 10 times, hence n = 10.
The probability that is lands tails up at least nine times is given by:
In which:
Hence:
0.0108 = 1.08% probability of the coin landing tails up at least nine times.
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1
By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is
Sequence is collection of numbers with some pattern .
Given sequence
We can see that
and
Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2
Now term of this Geometric progression can be written as
So summation of 15 terms can be written as
By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is
To learn more about Geometric progression visit : brainly.com/question/14320920
Total number of 10 grader students = 260 students.
Total number of students who rides the bus and they are of 10th grader = 150 students.
Probability (a student rides the bus given that they are a 10th grader) =
Therefore,
P(E) =
Dividing top and bottom by 10, we get
P(E) = 15/26.
In decimals 0.577.
Therrefore, correct option is C) 150/260 = 15/26 = .577.