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3 years ago

8

Which of the following shows the graph of y = 2 l n x

2 answers:

Effectus [21]3 years ago

5 0

Answer:

B.

Step-by-step explanation:

tatyana61 [14]3 years ago

4 0

Answer

The answer is B on EDGE 2020

Step-by-step explanation:

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Simplify the expression.<br> 28 + 4<br> 2<br> A. 9<br> B. 11<br> C. 16<br> D. 22

padilas [110]

Answer:

C) 16

Step-by-step explanation:

$\dfrac{28+4}{2}=\dfrac{32}{2}=16$

8 0

2 years ago

Read 2 more answers

Calculate the area of triangle ABC with altitude BD, given A (−6, 0), B (0, 0), C (0, 6), and D (−3, 3).

nata0808 [166]

Answer:

18 unit²

Step-by-step explanation:

If BD is altitude then AC is the base.

<u>The length of AC is:</u>

AC = $\sqrt{6^2+6^2} = 6\sqrt{2}$

<u>The length of BD is:</u>

BD = $\sqrt{3^2 + 3^2} = 3\sqrt{2}$

<u>The area is:</u>

A = 1/2bh
A = 1/2 * $6\sqrt{2} *3\sqrt{2}$ = 18 unit²

4 0

3 years ago

Read 2 more answers

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

max2010maxim [7]

Answer:

I guess 400g good for your diet. and health

3 0

3 years ago

(-16,-4),(8,-2) in a graph NOWW!!!!

Charra [1.4K]

Answer:

Hope this helps

6 0

3 years ago