If a and b are rational numbers and 6/(3√2-2√3 ) = a √2-b √3 , then find the values of a and b.
1 answer:
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SOLUTION
From the sequence give
–3, 1, 5, 9, . . .
The first term, a = -3
The common difference, d = 4 (gotten by adding 4 to the next term).
The number of terms required n = 6.
Formula for sum of an arithmetic sequence is given by
Substituting these values into the equation above we have
Hence, the answer is 42, option B