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Jet001 [13]
4 years ago
5

Which of the following statements about the number line is true? A. Numbers get smaller as you move to the left on the number li

ne. B. Numbers get larger as you move to the left on the number line. C. Number lines can't help you compare numerals. D. Number lines end with the number 10.
Mathematics
1 answer:
Naily [24]4 years ago
3 0
A. Numbers get smaller as you move to the left on the number line.
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A 6-pound watermelon costs $2.40 before a 30% discount. Which equation will allow you to find the discounted price of the waterm
V125BC [204]

Answer:

$1.68

Step-by-step explanation:

2.40 x .70 =1.68

8 0
3 years ago
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Let y be a random variable with p(y) given in the accompanying table. find e(y ), e(1/y ), e(y 2 − 1), and v(y ). y 1 2 3 4 p(y)
Studentka2010 [4]
<span>E[Y] = 0.4·1 + 0.3·2 + 0.2·3 + 0.1·4 = 2 E[1/Y] =0.4·1/1 + 0.3·1/2 + 0.2·1/3 + 0.1·1/4 = 0.4 + 0.15 + 0.0666 + 0.025?0.64 V[Y] =E[Y2]-E[Y]2= (0.4)·12+(0.3)·22+(0.2)·32+(0.1)·42-22= 0.4+1.2+1.8+1.6-4= 5-4 = 1</span>
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4 years ago
Which statement describe a polygon best ?
Bezzdna [24]
I believe that the best answer among the choices provided by the question is <span>2) figure that has 3 or more unequal length sides.</span>
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8 0
3 years ago
Which point lies on the graph of y = 2?A. (1.2)B. (1-2)C. (2, 18)D.(3, 2)
irinina [24]

A garph y=2 represents a line parallel to the x axis with the y coordinate equal to 2.

The point which lies on the y=2 graph has its y coordinate equal to 2.

In the given options, (3,2) is the coordinate with the y coordinate equal to 2.

Hence, (3,2) lies on the graph of y = 2.

Option (D) is the answer.

3 0
1 year ago
Element X decays radioactively with a half life of 11 minutes. If there are 870 grams
exis [7]

Answer:

27.5 minutes

Step-by-step explanation:

Using,

R/R' = 2ᵃ/ᵇ------------------ Equation 1

From the equation,

R = mass of Element X before radioactive decay, R' = mass of element X after radioactive decay, a = Time taken, b = half life.

Given: R = 870 grams, R' = 154 grams, b = 11 minutes.

Substitute these values into equation 1

870/154 = 2ᵃ/¹¹

(870/154)¹¹ = 2ᵃ

Solve for a

2ᵃ = (5.649)¹¹

2ᵃ = 187061.26

Taking the logarithm of both side,

Log2ᵃ = Log(187061.26)

⇒ a = log(187061.26)/log2

a = 8.272/0.301

a = 27.5 minutes

5 0
3 years ago
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