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sertanlavr [38]
3 years ago
12

algebra nation! i cant tell the sum or product of rational and irrational numbers added or multiplied together! someone explain

:)

Mathematics
1 answer:
Kamila [148]3 years ago
7 0

Answer

Step-by-step explanation:

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Help me fast I need please
ale4655 [162]

Answer:

2/9

Step-by-step explanation:

Since there are 18 total eggs (cracked, white, brown) we can say that the denominator will be 18.

There are 8 white eggs, and when half of those are cracked there will be 4 uncracked and 4 cracked, so 4/18.

Simplify 4/18 to 2/9 and there is your answer.

4 0
3 years ago
Which expression shows a sum of three terms.
vladimir1956 [14]

Answer:  B) 3+y+3

This can be simplified to y+6, but the current un-simplified expression has 3 terms.

======================================

Explanation:

Terms are separated by a plus sign. If you had something like 10x-5y, then you would write that as 10x+(-5y) showing that 10x and -5y are the two terms.

Choices A and C, xy and 6y respectively, have one term each. They are considered monomials. Mono = one, nomial = name.

Choice D is the product of the constant 3 and the binomial y+3. Binomials have two terms.

Only choice B has three terms, though we can simplify it down to two terms. I have a feeling your teacher doesn't want you to simplify it.

5 0
3 years ago
Some students reported how many pets they had. The dot plot shows the data collected: A dot plot is titled Students Pets and lab
hichkok12 [17]

Answer:B

Step-by-step explanation:I just know

4 0
3 years ago
The angles shown are supplementary. What is the value of x ?
almond37 [142]

Answer:

D

Step-by-step explanation:

This is because if u subsitute x with 17, 17x5 is 85 and 85+95= 180

5 0
3 years ago
Read 2 more answers
A city has a population of 400,000 people. Suppose that each year the population grows by 6.25%. What will the population be aft
Elena L [17]
6.25%=0.0625

P(t) = Initial Population * (1 + rate)^t

P(t) = 400,00*(1+0.0625)^t
P(t)= 400,00*(1+0.0625)^15
Pt=400
4 0
2 years ago
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