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3 years ago

Number 5. Need to write an equation

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

8 0

3)
just graph x= -3, y=0 and x=-2, y=3 and connect them
5)
315/3 = 525/5
= 105

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2x−8=20 steps to solving

Art [367]

Add 8 to both sides
2x = 28
Divide 2 to both sides
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3 years ago

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Need help asap willing to give a lot of points!

Zielflug [23.3K]

Answer:

$\fbox {See below} \downarrow$

Step-by-step explanation:

Question 1

Part (a) :

⇒ 6 × 6 × 6 × 6 × 6 × 6 × 6 = 6ˣ

⇒ 6⁷ = 6ˣ

⇒ x = 7

Part (b) :

⇒ y² = 169

⇒ √y² = √169

⇒ y = ± 13

⇒ y = 13, y = -13

Question 2

Part (a) :

⇒ (√5)² × (√3)²

⇒ 5 × 3

⇒ 15

Part (b) :

⇒ (∛9)³ × (√30)²

⇒ 9 × 30

⇒ 270

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2 years ago

For some reason it says square but please help! I need to know step by step what to do.

quester [9]

Answer:

8.06 inches

Step-by-step explanation:

The diagram shows a rectangle with width of 4 inches and area of 28 square inches.

Use area formula:

$A_{\text{rectangle}}=\text{Width}\times \text{Length}$

So,

$28=4\times \text{Length}\Rightarrow \text{Length}=\dfrac{28}{4}=7\ \text{inches}$

By the Pythagorean theorem,

$\text{Diagonal}^2=\text{Width}^2+\text{Length}^2\\ \\\text{Diagonal}^2=4^2+7^2\\ \\\text{Diagonal}^2=16+49\\ \\\text{Diagonal}^2=65\\ \\\text{Diagonal}=\sqrt{65}\approx 8.06\ \text{inches}$

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3 years ago

What is the first and second derivative of xe^(2x)?

Nimfa-mama [501]

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3 years ago

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Yezenia is filling up her outdoor swimming pool to get ready for summer time. She leaves the garden hose running for 1000 minute

Charra [1.4K]

Answer:

15.46 gallons per minutes

Step-by-step explanation:

Garden hose was running for 1000 minutes

Volume of the pool = 15,460 gallons

What is the approximate rate at which water leaves the garden hose?

Rate at which water leaves the garden hose = Volume of the pool / running time of the hose

= 15,460 gallons / 1000 minutes

= 15.46 gallons per minutes

Rate at which water leaves the garden hose = 15.46 gallons per minutes

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3 years ago