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Yakvenalex [24]
2 years ago
15

Q4.

Mathematics
1 answer:
goblinko [34]2 years ago
3 0

The coding of the statistic is used to make it easier to work with the large sunshine data set

  • The mean of the sunshine is 3.05\overline 6
  • The standard deviation is approximately  <u>18.184</u>

<u />

Reason:

The given parameters are;

The sample size, n = 3.

∑x = 947

Sample corrected sum of squares, Sₓₓ = 33,065.37

The mean and standard deviation = Required

Solution:

Mean, \ \overline x = \dfrac{\sum x_i}{n}

The mean of the daily total sunshine is therefore;

Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6

s = \dfrac{x}{10 } - \dfrac{1}{10}

  • E(s) = \dfrac{Ex}{10 } - \dfrac{1}{10}

E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6

  • The mean ≈ 3.05\overline 6

Alternatively

,The \ mean \  of \  the \  daily  \ total  \ sunshine,  \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6

The mean of the daily total sunshine, \overline s ≈3.05\overline 6

  • Var(s) = Var \left(\dfrac{x}{10 } - \dfrac{1}{10} \right)

Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)

Therefore;

Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537

Therefore;

  • s = \sqrt{330.6537} \approx 18.184

The standard deviation, s_s ≈ <u>18.184</u>

Learn more about coding of statistic data here:

brainly.com/question/14837870

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First you need to find the slope of your original equation.
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That's the original equation rewritten in slope intercept form.
The m represents the slope, so this equation's slope is 1/5.

Because you are given a point, and now you have a slope, the best and easiest route is using point slope form.
I've seen different versions of the equation base but I prefer y - y(sub1) = m(x - x(sub1))
But since I can't use subscripts in this, I'll use the one with h and k. The h is the x value of the point, and the k is the y value.
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I hope that helps. If anything didn't make sense, feel free to ask me.
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