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meriva
3 years ago
6

20 is what percent of 52? Round your answer to the nearest tenth.

Mathematics
2 answers:
Schach [20]3 years ago
7 0
20/52 = b/100
20 x 100/52 x b
2000/ 52b
b = 38.5

Explanation:

b is a variable that stands for the unknown quantity
Write 20/52 as equal to b/100
Next we cross multiply 20 by 100 = 2000 and 52 by b = 52b
2000/52b is equal to 38.46 but roundest to the nearest tenth it is 38.5

bearhunter [10]3 years ago
6 0

Answer:

88.3%

93.6%

98.6%

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Please help me I have no clue how to do it.<br><br><br> Thanks,<br><br> Sincerely, Juanito
IrinaK [193]
I think there would be 24 combinations.
5 0
3 years ago
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Excited about the success of celebrity​ stamps, post office officials were rumored to have put forth a plan to institute two new
SVETLANKA909090 [29]

Answer:

E=2.8 m-40

Step-by-step explanation:

We konw that  30°E=25°M and 310°E=125°M

so if we want to write an ecuation that linearly relates E with M, we can use the formula of the line that crosses two points:

Y-y1= (y2-y1)/(x2-x1)*(X-x1)

In thts case:

  • Y=E
  • y1= E1= 30
  • y2= E2=310
  • x1= M1= 25
  • x2=M2=125

so

E-E1= (E2-E1)/(M2-M1)* (M-M1)

E-30 = (310-30)/(125-25)*(M-25)

E-30 =280/100 *(M-25)

E-30 =2.8 M- 280*25/100

E-30 =2.8 M-70

E= 2.8 M-70+30

E=2.8 M-40

Good luck!

8 0
3 years ago
Find each measure for A and B​
siniylev [52]

Answer:

b = 22

Step-by-step explanation:

74 + 74

= 148

180 - 148

= 22

i hope this work for you

7 0
2 years ago
1. spotlight is placed 25 feet from a flag that is 20 feet high Spotlight Which expression can be used to find the angle of elev
Ganezh [65]

Answer:

Im not entirely sure this is right but

0 = tan^-1(20 ÷ 25)

0 ≈ 38.65°

hope i helped lol

5 0
2 years ago
A university with a high water bill is interested in estimating the mean amount of time that students spend in the shower each d
Bas_tet [7]

Answer: (4.0845,\ 6.5755)

Step-by-step explanation:

As per given , we have

n = 11

\overline{x}=5.33\\\\ s=1.33

Since population standard deviation is missing, so we use t-test.

Critical t-value for 99% confidence :

t_{\alpha/2,\ n-1}=3.106   [using two-tailed t-value table]

Confidence interval :

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}\\\\= 5.33\pm (3.1060)\dfrac{1.33}{\sqrt{11}}\\\\\approx5.33\pm1.2455\\\\=(5.33-1.2455,\ 5.33+1.2455)\\\\=(4.0845,\ 6.5755)

Hence,  99% confidence interval for the mean amount of time that students spend in the shower each day.= (4.0845,\ 6.5755)

7 0
3 years ago
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