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r-ruslan [8.4K]
2 years ago
12

the fifth term of an arithmetic progression is 40 and the seventh term is 28 more than the 3rd term. Find the first and 10th ter

m.​
Mathematics
1 answer:
wel2 years ago
3 0

Answer:

Step-by-step explanation:

t5 = a + (5-1)d

t5 = a + 4d

40 = a + 4d

t3 = a + 2*d

t7 = a + 2d + 28 = a + 6d

Start with the seventh term which has 2 equal answers

a + 2d + 28 = a + 6d                    Subtract a from both sides

2d + 28 = 6d                                Subtract 2d from both sides

28 = 4d                                         Divide by 4

28/4 = d

d  = 7

==================

t5 = a + 4d = 40

a + 4*7 = 40

a = 40 - 28

a = 12

===================

First term is 12

10th term is

t10 = 12 + (10 - 1)*7

t10 = 12 + 9*7

t10 = 75

Interesting question. Thanks for posting

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Answer:

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

Step-by-step explanation:

we have

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This is a vertical parabola open upward

The vertex is a minimum

The vertex is the origin (0,0)

g(x)=-5x^{2}+100x-450

This is a vertical parabola open downward

The vertex is a maximum

The first thing to note is that fx) is a parabola that opens up and g(x) opens down, so a reflection across the x-axis must have been applied.

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Convert to vertex form

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Complete the square

g(x)=-5(x^{2}-20x)-450

g(x)=-5(x^{2}-20x+100)-450+500

g(x)=-5(x^{2}-20x+100)+50

g(x)=-5(x-10)^{2}+50

The vertex is the point (10,50)

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To translate the vertex of (0,0) to (10,50)

The rule of the translation is

(x,y) ------> (x+10,y+50)

That means ----> The translation is 10 units at right and 50 units up

therefore

The transformations are

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

5 0
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1 year ago
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