Answer:
The answer to your question is: Y = (13, -14)
Step-by-step explanation:
Data
midpoint = mp = (6, -3)
one endpoint = X = (-1, 8)
second endpoint = Y = (x, y)
Formula
Xmp = (x1 + x2) / 2
Ymp = (y1 + y2) / 2
Process
x2 = 2xmp - x1
y2 = 2ymp - y1
x2 = 2(6) - (-1) y2 = 2(-3) - 8
x2 = 12 + 1 y2 = -6 - 8
x2 = 13 y2 = - 14
Y = (13, -14)
Answer:
I think the answer is 2
Step-by-step explanation:
1 significant figure would be 3000
<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>The height of a ball thrown into the air after t seconds have elapsed is:</u></em>

<em><u>What is the first time, t, when the ball will reach a height of 20 feet?</u></em>
Substitute h = 20

<em><u>Solve by quadractic formula</u></em>




Rounding off we get,
t = 2.08 , t = 0.42
Thus the first time when the ball will reach a height of 20 feet is 0.42 seconds
Nope, but if you need help you can tell me what the questions are and I'll try solve them!