Which number contains digits where the hundreds digit is 10 times as great as the tens digit? 7,988 , 7,898 , 7,889

1 answer:

5 0

Answer : 7,889

Hundreds digit : 800
Tens digit : 80

800 ÷ 80 = 10 (800, the hundreds digit, is 10 times as great as the tens digit, 80)

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Can someone explain HOW to simplify this algebraic fraction, as in tell me why and what I need to do for each step : 1-n/n^2-1

Andreyy89

- I’m assuming the expression implies the following:

(1-n)/(n^2 - 1)

The steps goes as follows:

= -(n-1)/(n^2-1) (factored a negative out)
= -(n-1)/[(n+1)(n-1)] (Factored denominator into a difference of squares, but don’t just blindly accept the fact, expand it and you should get the original denominator)

At this point, the (n-1) terms cancel, as you should know: a real number, besides 0, over itself is 1.

= -1/(n+1) , which is the answer

Note: You could also see it as 1/-(n+1) or 1/(-n-1)

8 0

2 years ago

Simplify. (√5+4) (√5 - 2)

son4ous [18]

Answer:

2√5 - 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS