Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.
<u>Solution:</u>
Given that,
Total circulation of local newspaper in 2000 = 3250
Total circulation of local newspaper in 2001 = 3640
Total circulation of local newspaper in 2002 = 4100
<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>
<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>
As we can see 12% < 12.6%
So period of 2001 to 2002 has higher increase percentage.
1/49=x^2 where x is the side of the square
1/49=(1/7)^2, so the side length of the square is 1/7
|DF| = |DE| + |EF|
|DF| = 9x -36
|DE| = 47
|EF| = 3x+10
Substitute:
9x - 39 = 47 + 3x + 10
9x - 39 = 3x + 57 |+39
9x = 3x + 96 |-3x
6x = 96 |:6
x = 16
Put the value of x to the equation |EF| = 3x + 10
|EF| = (3)(16) + 10 = 48 + 10 = 58
Answer: |EF| = 58
The missing values in the inequality problem are;
A = -9
B = 72
C = 22
<h3>What is the explanation for the above?</h3>
5p - 8 (p + 1) > 16 ......................... (1) Given
5 (-10) - 8 (-10 +1) > 16 ...................... (2) Given
Where P is equal to 10 [Given in the second line as given in equation 2 above; Hence,
Substitute 10 for p
⇒ 5 (-10) - 8(-10+1)> 16
⇒ -50 -8(-9) > 16
⇒ -50 + 72 > 16
Hence
22 > 16 → T
Please note that T is symbolic of "True" that is
it is true that 22 is greater than 16.
Learn more about inequality problems:
brainly.com/question/11613554
#SPJ1
