1. Points M and N have coordinates (-4,0) and (4,2), respectively.
Then vector 
is perpendicular to the neede line.
2. Write the equation of line that passes through the point P(2,-4) and is perpendicular to vector 
3. Find the point on x-axis, that lies on the perpendicular line.
When y=0, then 4x-4=0, x=1 and point (1,0) lies on perpendicular line.
Answer: correct choice is C.
I thing the answer you are looking for is 49
Answer:
See below ↓↓
Step-by-step explanation:
<u>Equation of line k</u>
- y = mx + b
- m = Δy/Δx (ratio of change in y to change in x) = 2/3
- b = 3 (as y-intercept is [0,3])
- ⇒ y = 2/3x + 3
<u />
<u>a. parallel line</u>
- For parallel lines, slope (m) remains the same, but the y-intercept (b) changes
- ⇒ <u>y = 2/3x + 1</u>
<u></u>
<u>b. perpendicular line</u>
- For perpendicular lines, the slope (m) is the negative reciprocal of the original line and the value of b stays the same [it can be any point as long as it intersects the line]
- ⇒ <u>y = -3/2x + 1</u>
D. 44
4.5•2=9
9•3.14=28.26
28.28 rounds down to 28cm
11.5•2=23
23•3.14=72.22
72.22 rounds down to 72cm
72-28=44
