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3 years ago

ILL MARK BRAINLIEST!!! PLEASE HELP!

Mathematics

1 answer:

eduard3 years ago

3 0

Answer:

The quadratic equation is X^2 -26X +144=0

Step-by-step explanation:

You can do it shortly by using the formula

X^2-(sum)x+ product

which will give you

X^2- (8+18)x+8×18

=X^2 -26x +144

=X^2 -8x-18x + 144

=(X^2-8x)(-18x+144)

=X(X-8)-18(x-8)=0

(X-18)(X-8)=0

X-18=0 And X-8=0

X=18 X=8

. Therefore the quadratic equation is X^2 -26X +144

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If f(x) = negative 3X -2, what if f(-5)?

Scrat [10]

Answer:

f(- 5) = 13

Step-by-step explanation:

Substitute x = - 5 into f(x)

f(x) = - 3x - 2 , then

f(- 5) = - 3(- 5) - 2 = 15 - 2 = 13

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3 years ago

If f(x) = 1/9 x - 2, what is f-1 (x)

Snowcat [4.5K]

$f(x) = \frac{1}{9} x - 2 \\$

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3 years ago

Simplify the product 7x(x+4)

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=7x2+28x
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3 years ago

Read 2 more answers

I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know

azamat

By definition of conditional probability,

$P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}$

$=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}$

Assuming a standard 6-sided fair die,

if $X_1=4$ , then $X_1+X_2=7$ means $X_2=3$ ; otherwise,
if $X_2=4$ , then $X_1=3$ .

Both outcomes are mutually exclusive with probability $\frac1{36}$ each, hence total probability $\frac2{36}=\frac1{18}$ .

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

and so a sum of 7 occurs $\frac6{36}=\frac16$ of the time.

Then the probability we want is

$P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13$

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3 years ago

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Gwar [14]

Answer:

Step-by-step explanation:

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3 years ago