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3 years ago

ILL MARK BRAINLIEST!!! PLEASE HELP!

Mathematics

1 answer:

eduard3 years ago

3 0

Answer:

The quadratic equation is X^2 -26X +144=0

Step-by-step explanation:

You can do it shortly by using the formula

X^2-(sum)x+ product

which will give you

X^2- (8+18)x+8×18

=X^2 -26x +144

=X^2 -8x-18x + 144

=(X^2-8x)(-18x+144)

=X(X-8)-18(x-8)=0

(X-18)(X-8)=0

X-18=0 And X-8=0

X=18 X=8

. Therefore the quadratic equation is X^2 -26X +144

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Y=6x-11<br> -2x-3y=-7 gnjjj

KiRa [710]

Answer:

x=2 y=1

Step-by-step explanation:

Solve the equations by substituting y=6x-11 into -2x-3y=-7.

-2x-3(6x-11)=-7

-2x-18x+33=-7

-20x+33=-7

-20x=-7-33

-20x=-40

x=2

To find y, substitute this value into the equation and solve for y.

y=6(2)-11

y=12-11

y=1

7 0

3 years ago

Kayla squared a number x and added this result to -6.5. This gave her an answer of 42.5.

ladessa [460]

Answer:

7, -7

Step-by-step explanation:

x^2-6.5= 42.5 add 6.5 to both sides

x^2= 49

The square root of 49 is 7 and -7.

7 0

3 years ago

Check all that apply. pi/4 is the reference angle for:

ANEK [815]

Answer:

answer is c

I took a quiz with the question and got 100%

3 0

2 years ago

If f(x)=2x^2+3 then f(x-1)=2x^2+4x+5 <br> true or false

TEA [102]

Hello from Hello from MrBillDoesMath!

Answer:

False.

Discussion:

See attached file for discussion.

Thank you,

MrB

7 0

4 years ago

When an object is thrown upwards with a speed of 64 ft/sec, its height above the ground is given by the function h(t)=−16t2+64t

Svet_ta [14]

Answer:

The object will reach its highest point 0.5 seconds after it has been thrown.

Step-by-step explanation:

The object reaches its maximum height when velocity is equal to zero, the velocity is the derivative of function height. That is:

$v(t) = \frac{d}{dt}h(t)$ (1)

Where $v(t)$ is the velocity of the object at time $t$ , in feet per seconds.

If we know that $h(t) =-16\cdot t^{2}+64\cdot t$ and $v(t) = 0\,\frac{ft}{s}$ , then the time when object reaches its highest point is:

$v(t) = -32\cdot t+64$

$-32\cdot t + 64 = 0$

$t = 0.5\,s$

The object will reach its highest point 0.5 seconds after it has been thrown.

3 0

2 years ago