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Andreas93 [3]
4 years ago
7

a business has a goal if selling 500 bags of chips. with 3 days left they have 322 To go. at least how many do they need to aver

age per day to next their goal
Mathematics
2 answers:
slavikrds [6]4 years ago
8 0

They have to sell an average of 108 bags of chips a day for the last 3 days. 322/3 = 107.3333, or approximately 108.

Aloiza [94]3 years ago
3 0

The equation for average is whole/part=average so, 322/3=107.3

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PSYCHO15rus [73]

I am going to use C to represent cookbook and N to represent N. I find that easier to remember which is which.

Day 1: 5C + 3N = 167

Day 2: 3C + 1N = 89

We need to solve one of these equation for either the C or N. I always choose the easiest one! Day 2 looks like the one.

3C + 1N = 89 (I am doing to solve for N because we won't have a fraction)

1N=89-3C

N=89-3C

Now we take this solution for N and put it into our first equation.

5C + 3(89-3C) = 167 (We need to distribute)

5C + 267 - 9C = 167 (Use subtraction to move C values to the right and numbers to the left)

267-167 = 9C-5C

100 = 4C

25 = C $25 for the Cookbooks.


Now, we have to go back and solve for N by putting $25 in for C in the second equation.

N=89-3(25)

N=89-75

N=14 dollars for each novel.

Check by putting both back into the first equation:

5C + 3N = 167

5(25) + 3(14) = 167. It checks out!


3 0
3 years ago
15.09 ÷ 0.01 = ?<br> 267.4 ÷ 1/10 = ?
Masja [62]

Answer:

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8 0
3 years ago
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atroni [7]

Answer:

The width of the confidence interval is going to be wider

Step-by-step explanation:

When we Increase the level of confidence without changing the sample size the width of the confidence interval is going to be affected in the following way;

The margin of error (M.E) is going to be larger or be increased. This increase is due to the fact that the critical value is going to increase. Then the increased margin of error would cause the width of the confidence interval to become wider.

This answers your question.

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Answer:

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Answer:

the answer is c) or 6. I hope it helps

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