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3 years ago

- 2/3 × 3/5 + 5/2 - 3/5 × 1/6

Mathematics

2 answers:

elena-s [515]3 years ago

7 0

Answer:

Step-by-step explanation:

(-2/3 x 3/5) + 5/2 - (3/5 x 1/6)

-2/3 x 3/5 = -6/15 = -2/5 (simplified)

3/5 x 1/6 = 3/30 = 1/10 (simplified)

Changed equation: -2/5 + 5/2 - 1/10

-2/5 x 2 = -4/10

5/2 x 5 = 25/10

Changed equation: -4/10 + 25/10 - 1/10

Answer: 20/10 = 2 (simplified answer)

madam [21]3 years ago

5 0

First start by multiplying:
-6/15 + 5/2 -3/30

then u can simplify the fractions, -6/15=-2/5 and -3/30=-1/10

-2/5 + 5/2 - 1/10, now find a common denominator in this case 10
-4/10 + 25/10 - 1/10

now add and subtract normally

answer:20/10 or 2

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Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

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(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

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Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

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- 2/3 × 3/5 + 5/2 - 3/5 × 1/6​

- 2/3 × 3/5 + 5/2 - 3/5 × 1/6