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brilliants [131]
3 years ago
11

A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what

is the probability that two red marbles are drawn?
A) 4/25
B) 3/20
C) 18/125
D) 1/6

OFFERING 20 POINTS!!
Mathematics
2 answers:
Firdavs [7]3 years ago
8 0

Answer:

B 3/20

Step-by-step explanation:

its not C

cluponka [151]3 years ago
4 0

<u>Problem</u>

A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?

<u>Work </u>

Probability = no. of favorable outcomes /total no. of outcomes

Probability of getting a blue marble=5/5+6+9=5/20

Probability of getting a red marble=6/20−1=6/19

5/20×6/19

<u>Answer</u>

3/20

So it is C.

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Read 2 more answers
4-(2x-3)=3 whats the answer
Oxana [17]

Hello there.

Explanation:

↓↓↓↓↓↓↓↓↓↓

4-(2x-3)=3

First, subtract by 4 from both sides.

4-(2x-3)-4=3-4

Second, simplify.

-(2x-3)=-1

Third, divide by -1 from both sides.

\frac{-(2x-3)}{-1}=\frac{-1}{-1}

Fourth, simplify.

2x-3=1

Next, add by 3 from both sides.

2x-3+3=1+3

Then simplify.

2x=4

Therefore, divide by 2 from both sides.

\frac{2x}{2}=\frac{4}{2}

Finally, simplify.

x=2

<u><em>Answer⇒⇒⇒⇒x=2</em></u>

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

8 0
3 years ago
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