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Tema [17]
4 years ago
15

a grandfather clock keeps time by making 60 swings in 60 seconds. after two hours the clock is slow by 1.5 minutes. explain both

quantitatively and qualitatively a solution that will fix the clock
Physics
1 answer:
Olenka [21]4 years ago
4 0

Answer:

Increasing the length of the pendulum quantitatively increases the time period of oscillation.

Explanation:

Given data,

A grandfather's clock keeps time by making 60 swings in 60 seconds.

After two hours the clock is slow by 1.5 minutes.

The time period of oscillation is given by the formula,

                           <em> t=2\pi \sqrt{\frac{l}{g}}</em>

Where 'l' is the length of the pendulum clock.

Increasing the length of the pendulum quantitatively increases the time period of oscillation.

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A comet of mass 1.20 × 10¹⁰kg moves in an elliptical orbit around the Sun. Its distance from the Sun ranges between 0.500 AU and
irina [24]

The eccentricity of its orbit is $$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

<h3>What is mass?</h3>
  • Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.
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The length of the semi-major axis is calculated as follows:

where, $G=6.67 \times 10^{-1} \mathrm{~m}^3 / \mathrm{kgs}$

$M=1.99 \times 10^{30} \mathrm{~kg}=$mass of sur

$m=1.20 \times 10^{10} \mathrm{~kg}$ - a mass of the comet

$$\begin{aligned}\therefore \quad \text { At aphelion, } r &=50 \times U \\&=50 \times 1.496 \times 10^{11} \mathrm{~m} . \\U=-\frac{6.67 \times 10^{-11} \times \mathrm{m} 1.99 \times 10^{30} \times 1.20 \times 10^{10}}{50 \times 1.496 \times 10^{11}} \\U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

$$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

To learn more about mass, refer to:

brainly.com/question/3187640

#SPJ4

4 0
2 years ago
What is <br> general education
ddd [48]
Please follow me and mark me as brainiest

7 0
3 years ago
The path a projectile takes is known as the;
Fantom [35]

B. trajectory

because it is a set projectile wether or not it was calculated

plz mark brainliest

8 0
4 years ago
Read 2 more answers
The voltage applied across a given parallel-plate capacitor is doubled. How is the energy stored in the capacitor affected?
ikadub [295]

Answer:

The energy stored in the capacitor quadruples its original value.

Explanation:

The energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance

V is the voltage across the plates

The capacitance, C, depends only on the properties of the capacitor, so it does not change when the voltage applied is changed.

Instead, in this problem the voltage applied is doubled:

V' = 2V

So the new energy stored is

U'=\frac{1}{2}C(2V)^2=4(\frac{1}{2}CV^2)=4U

so, the energy stored has quadrupled.

8 0
4 years ago
According to the text, how do small animals likemicerats,
Lesechka [4]

Answer:

According to the text you have given above,

Pigeons probably eat the plants from people's gardens.

Mice and Rats get food from the trash people.

(I guess this answer will help you :-)

4 0
4 years ago
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