Well, in some systems the atoms melt or burn or change state like from liquid to gases when they reach a certain temperature. This could decrease the energy in the system.
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Answer:
Potential at B would be 100V
Explanation:
The electric potential is defined as the work done to bring a unit positive charge from infinity to some point in the field.
We always determine the potential with respect to some reference point. Let the potential at A be zero. If the potential at B is V, then work done to bring charge q from A to B = qV
which is the electric potential energy.
If instead we use some charge Q, the electric potential <em>energy</em> will be QV, but the electric potential will always be V.
Answer:
Option C. 4 Hz
Explanation:
To know the correct answer to the question given above, it is important we know the definition of frequency.
Frequency can simply be defined as the number of complete oscillations or circles made in one second.
Considering the diagram given above, the wave passes through the medium over a period of one second.
Thus, we can obtain the frequency by simply counting the numbers of complete circles made during the period.
From the diagram given above,
The number of circles = 4
Thus,
The frequency is 4 Hz
Answer:
(a) v = 65.35 m/s
(b) ac = 82.16 m/s²
Explanation:
Kinematic of the blades of the wind turbine
The blades of the wind turbine describe circular motion and the formulas that apply to this movement are as follows:
v = ω * R Formula (1)
Where:
v : tangential velocity (m/s)
ω : angular velocity (rad/s)
R : radius of the particle path (m)
The velocity vector is tangent at each point to the trajectory and its direction is that of movement. This implies that the movement has centripetal acceleration (ac):
ac = ω²* R Formula (1)
ac : centripetal acceleration (m/s²)
Data:
ω= 12 rpm = 12 rev/min
1 rev = 2π rad
1 min = 60 s
ω= 12 rev/min = 12 (2π rad)/(60 s)
ω = 1.257 rad/s
R = 52 m
(a)Tangential velocity at the tip of a blade (v)
We apply the formula (1)
v = ω* R
v = ( 1.257)* (52) = 65.35 m/s
(a) Centripetal acceleration at the tip of a blade (ac)
We apply the formula (2)
ac = ω²*R
ac = ( 1.257)²* (52) = 82.16 m/s²