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Minchanka [31]
3 years ago
12

Why does paramcium never die​

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0

Answer:

the paracium never dies because it keeps on reproducing

Step-by-step explanation:

the paracium lets say it starts as 1

and then taht 1 divides inti

1/2 and 1/2 and that 1/2 turns into 1

and it keeps on dividing and multiplying

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Solve for x in the equation? <br><br> a/(2x-c) = -1
Svet_ta [14]

Answer:

\frac{c-a}{2}

Step-by-step explanation:

given \frac{a}{2x-c} = - 1 ( cross- multiply )

- (2x - c ) = a ( distribute left side )

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x = \frac{c-a}{2}

4 0
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Read 2 more answers
Find the difference
Makovka662 [10]

Answer:

-5n^2 +2n +5

Step-by-step explanation:

( -4n^2 +2n) - (n^2 -5)

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( -4n^2 +2n) - n^2 +5

Combine like terms

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7 0
3 years ago
Identify quadrilateral ​
Sholpan [36]

14. trapezoid

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15. rhombus

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16. kite

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4 0
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A complex number z_1z 1 ​ z, start subscript, 1, end subscript has a magnitude |z_1|=6∣z 1 ​ ∣=6vertical bar, z, start subscript
aliina [53]

Answer:

The answer is "\bold{9.19- 9.19\ i}"

Step-by-step explanation:

When the value of z_1 has the following properties:

\to |z_1| =13

\theta = 315^{\circ} \\\\ = 1.75 \pi\ \ \ \ \ \ \ \ \ \ \ \ \ \  \ _{where} \ \ (\pi = 180^{\circ})

Calculating the value of z_1 :

= 13 \times [ \cos(1.75 \pi ) + i \sin(1.75 \pi) ] \\\\=  13 \times[\cos(1.75 \pi - 2\pi ) + \ i \sin(1.75 \pi - 2\pi )]\\ \\= 13 \times [\cos(-0.25 \pi ) +\  i \sin(-0.25 \pi) ]\\\\= 13 \times [0.707106781 - 0.707106781]\\\\ =9.19 - 9.19\ i \\\\

3 0
3 years ago
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