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2 years ago

Find the 16th term in the geometric series where the first term is 6 and the common ratio is 2.

Mathematics

1 answer:

deff fn [24]2 years ago

5 0

Answer: The first term of a GP is 6 if it's common ratio is 2 find the 6th term

The nth term is ar^(n-1)

So, for your GP, the 6th term is 6*2^5 = ___

Step-by-step explanation: 10:2021

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Answer:

x + 3y = 21

Step-by-step explanation:

$(x_{1},y_{1})=(12,3) \\\\(x_{2},y_{2})=(-3,8)\\\\Slope= \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\= \dfrac{8-3}{-3-12}= \dfrac{5}{-15}\\\\= \dfrac{-1}{3}$

Equation of the line: y =mx+ b

$y = \dfrac{-1}{3}x+b\\\\\\Plugin \ x = 12 \ and \ y=3 \ in \ the \ above \ equation\\\\3= \dfrac{-1}{3}*12+b\\\\3= -4+b\\\\3+4 = b\\\\b = 7\\\\\\\y= \dfrac{-1}{3}x+7\\\\$

Multiply the equation by 3

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