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irakobra [83]
3 years ago
10

Ugh algebra is grosss

Mathematics
1 answer:
sammy [17]3 years ago
3 0

The lines are proven to be parallel so that executes the two perpendicular choices, so I'm assuming it is 'The lines are parallel because the slopes are the same'...

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Help me please idk how to do it
frozen [14]
You do £68.85 - £15.30= (the answer)
Then you do the answer of that divided by 0.85
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3 years ago
What is the velocity of a car that is traveling north 290 kilometers in 5 hours?
Maksim231197 [3]

Answer:

58

Step-by-step Explanation: 290 / 5 = 58

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Find the equation of the line containing the point (3, 3) and parallel to the line
DIA [1.3K]

Answer:

y = 2x - 3

Step-by-step explanation:

Parallel lines have the same slope

only the constant changes

y = 2x + b

To find "b"

Plug in point (3, 3)

3 = 2(3) + b

3 = 6 + b

Subtract 6 from both sides

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The equation for the parallel line is

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2 years ago
Histogram can be drawn for equal and unequal classes. True/False​
Elis [28]

Answer:

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Step-by-step explanation:

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2 years ago
Find the sum of the first four terms of the geometric sequence shown below. 4​, 4/ 3​, 4/9​, ...
user100 [1]
It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is

S_4=4+\dfrac43+\dfrac49+\dfrac4{27}

It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.

Multiply the sum by 1/3 and you have

\dfrac13S_4=\dfrac43+\dfrac49+\dfrac4{27}+\dfrac4{81}

Now subtracting this from S_4 gives

S_4-\dfrac13S_4=4-\dfrac4{81}

That is, all the matching terms will cancel. Now solving for S_4, you
have

\dfrac23S_4=4\left(1-\dfrac1{81}\right)
S_4=6\left(1-\dfrac1{81}\right)
S_4=\dfrac{480}{81}=\dfrac{160}{27}
3 0
3 years ago
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