Answer:
28 + 8y - 8
Step-by-step explanation:
According to the problem;
-2(3x + 12y - 17x - 16y + 4)
Collecting like terms;
-2(3x -17x + 12y - 16y + 4)
-2(-14x - 4y + 4)
28 + 8y - 8
None of the options matches the correct answer.
Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place -
Number of ways for second place -
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place -
Number of ways for second place -
Total number of different tickets are possible is
Therefore, 4032 different tickets are possible.