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olganol [36]
3 years ago
10

The sum of the measures of two of the angles formed by the intersection of two lines is 114°. Find the measures of all angles. I

need four answers, as in four angles.
Mathematics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

Measures of all angles are 57°, 57°, 123°, 123°

Step-by-step explanation:

Given:

Sum of two angles = 114°

Find:

Measures of all angles

Computation:

Sum of all 4 angles = 360°

Sum of remain 2 angles = 360° - 114°

Sum of remain 2 angles = 246°

So, first two angles = 114° / 2 = 57°

Second two angles = 246° / 2 = 123°

So, measures of all angles are 57°, 57°, 123°, 123°

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Delicious77 [7]

Answer:

Option B is correct

Step-by-step explanation:

The multiply of matrix A by matrix B that is inverse of A, must result in an identity matrix that has form shown in option B

Hope this helps!

8 0
3 years ago
Help me please no one is answering i need help on math :(
Pani-rosa [81]

Answer:

3         3

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Step-by-step explanation:

For the time add 3 each time

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3 0
3 years ago
Read 2 more answers
Will pick BRAINLIEST!!
anygoal [31]
Hi there!
The question sounds really complex, but the mathematical operations behind it is figuratively simple. Here, we are told to find 19 (18.7 rounded up is 19) percent of 1,000. To do this, we can set up a proportion to model the whole scenario.
\frac{x}{1000} = \frac{19}{100}
Now, just solve for x by cross multiplying and simplifying.
\frac{x}{1000} = \frac{19}{100}

100x = 19000
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Therefore, 190 people out of 1,000 people leave out pertinent information on their IRS forms. Hope this helped and have a terrific day!
4 0
4 years ago
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It's in the picture plzz help
zaharov [31]

ANSWER:

Total monthly budget in dollar = $3665.

Now,

[i] Percent of taxes,

755/3665 × 100 = 20%

[ii] Percent of housing,

790/3665 × 100 = 22%

[iii] Percent of food,

350/3665 × 100 = 9%

[iv] Percent of savings,

700/3665 × 100 = 20%

[v] Percent of transportation,

245/3665 × 100 = 7%

[vi] Percent of clothing,

110/3665 × 100 = 3%

[vii] Percent of utilities,

185/3665 × 100 = 5%

[viii] Percent of entertainment,

110/3665 × 100 = 3%

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7 0
3 years ago
T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
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