3 years ago

Combine like terms 4y^2+4(7y^2-8)= please show your work

Mathematics

1 answer:

kirza4 [7]3 years ago

8 0

Answer:

32y^2-32

Step-by-step explanation:

4y^2+4(7y^2-8)

4y^2+28y^2-32

32y^2-32

if you need extra steeps explaining then plz let me know and I will help :)

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Evaluate the following expression for x=-2 -4x+8+2x+3

sergiy2304 [10]

Answer:

Step-by-step explanation:

x = 2

-4x+8+2x+3 = ?

-4 (-2) + 8 + 2 (-2) + 3 =

= 8 + 8 - 4 + 3

= 16 - 4 + 3

= 12 + 3

= 15

hopefully this helped you :)

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3 years ago

Find the area of a rectangle with a base of 5 feet and a height of 9 1/2 feet

gayaneshka [121]

The area of the rectangle is 47 1/2

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2 years ago

Find the slope given: (1,5) & (3,12)<br> m =

e-lub [12.9K]

Answer:

Rise (y) over Run (x)

12-5

------

3-1

7/2=m

Step-by-step explanation:

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3 years ago

Read 2 more answers

in a xy-coordinate system line 1 has a slope of -3. If the points (2,16 and (5,t) are on line 1, what is the value of t?

Dimas [21]

We can use the formula y2-y1/x2-x1 to find our answer. So, we have : t-16/5-2 = -3. We simplify that to t-16/3 = -3. We can then multiply both sides by 3 to get t-16 = -9. Then we can add 16 to both sides to get t = 7.

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3 years ago

Which expression is equivalent to √48x5, if x> 0?

Lerok [7]

Answer:

C. 4x²√(3x)

Step-by-step explanation:

if x > 0

$\sqrt{48x^{5}} =\sqrt{48} \times \sqrt{x^{5}}$

$=\sqrt{16\times 3} \times \sqrt{x^{4}\times x}$

$=\sqrt{16} \times \sqrt{3} \times \sqrt{x^{4}} \times \sqrt{x}$

$=4\times \sqrt{3} \times \sqrt{\left( x^{2}\right)^{2} } \times \sqrt{x}$

$=4\times \sqrt{3} \times x^{2}\times \sqrt{x}$

$=4\times x^{2} \times \sqrt{3} \times \sqrt{x}$

$=4\times x^{2}\times \sqrt{3x}$

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1 year ago