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3 years ago

6ax^2+6ax+6a find the greatest common factor?

Mathematics

2 answers:

adelina 88 [10]3 years ago

6 0

The GCF (Greatest Common Factor) is 6a.

grandymaker [24]3 years ago

4 0

You can factor out 6a:

6a(x²+x+1)

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Choose the set of numbers with an average of 8.

Anastaziya [24]

The correct answer is B

To find the average we add all the given numbers together then divide by how many numbers there are.

A is 7

B is 8

C is 9

5 0

2 years ago

Read 2 more answers

Explain how to estimate 36.8 + 231 two different ways

larisa [96]

You could do 37+230 or 40 + 235

5 0

3 years ago

Find the point of diminishing returns (x comma y )for the function R(x), where R(x) represents revenue (in thousands of doll

riadik2000 [5.3K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The point of diminishing returns (x , y ) is (11, 21462)

Step-by-step explanation:

From the question we are told that

The function is $R(x) = 10,000 -x^3 - 33x^2 + 800x , \ \ 0 \le x \le 20$

Here R(x) represents revenue (in thousands of dollars) and x represents the amount spent on advertising (in thousands of dollars).

Now differentiating R(x) we have

$R'(x) = -3x^2 +66x + 800$

Finding the second derivative of R(x)

$R''(x) = -6x +66$

at inflection point $R''(x) = 0$

So $-6x +66 = 0$

=> $x= 11$

substituting value of x into R(x)

$R(x) = 10,000 -(11)^3 - 33(11)^2 + 800(11) ,$

$R(x) = 21462$

Now the point of diminishing returns (x , y ) i.e (x , R(x) ) is

(11, 21462)

4 0

3 years ago

A group of four friends goes to the movies. Each friend pays for a ticket, a snack, ana

kvv77 [185]

Answer:4(1.5)

Step-by-step explanation:

5 0

3 years ago

The rate at which the temperature is dropping is 6t 5t2 degrees Celsius per hour t hours after sundown. How much had the tempera

Whitepunk [10]

Using a differential equation, it is found that the temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

<h3>What is the differential equation that describes the temperature in t hours after sundown?</h3>

The rate at which the temperature is dropping is $6t + 5t^2$ degrees Celsius per hour t hours after sundown, hence the <em>differential equation</em> is:

$\frac{dT}{dt} = 6t + 5t^2$

Applying <em>separation of variables</em>, we find the solution as follows:

$\frac{dT}{dt} = 6t + 5t^2$

$dT = (6t + 5t^2) dt$

$\int dT = \int (6t + 5t^2) dt$

$T(t) = \frac{5t^3}{3} + 3t^2 + T(0)$

In which T(0) is the temperature at sundown.

In 3 hours, the change will be of:

$C = T(3) - T(0) = \frac{5t^3}{3} + 3t^2|_{t = 3}$

Hence:

$\frac{5(3)^3}{3} + 3(3)^2 = 45 + 27 = 72$

The temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

You can learn more about differential equations at brainly.com/question/24348029

5 0

2 years ago