All categories

2 years ago

6ax^2+6ax+6a find the greatest common factor?

Mathematics

2 answers:

adelina 88 [10]2 years ago

6 0

The GCF (Greatest Common Factor) is 6a.

grandymaker [24]2 years ago

4 0

You can factor out 6a:

6a(x²+x+1)

You might be interested in

Is anyone able to figure this out, I can't do this

katrin [286]

Answer:

C. √2 - 1

Step-by-step explanation:

If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)

Let r = the radius of the small circle

Using Pythagoras' Theorem $a^2+b^2=c^2$

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

to find the diagonal of the square:

$\implies r^2 + r^2 = c^2$

$\implies 2r^2 = c^2$

$\implies c=\sqrt{2r^2}$

So the diagonal of the square = $\sqrt{2r^2}$

We are told that the radius of the large circle is 1:

⇒ Diagonal of square + r = 1

$\implies \sqrt{2r^2}+r=1$

$\implies \sqrt{2r^2}=1-r$

$\implies 2r^2=(1-r)^2$

$\implies 2r^2=1-2r+r^2$

$\implies r^2+2r-1=0$

Using the quadratic formula to calculate r:

$\implies r=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\implies r=\dfrac{-2\pm\sqrt{2^2-4(1)(-1)}}{2(1)}$

$\implies r=\dfrac{-2\pm\sqrt{8}}{2}$

$\implies r=-1\pm\sqrt{2}$

As distance is positive, $r=-1+\sqrt{2}=\sqrt{2}-1$ only

5 0

2 years ago

Read 2 more answers

Which of the following is the simplest form of this expression?

Readme [11.4K]

The numerator could be written a⁴/⁵

The denominator could be written a²/³

Now solve ( a⁴/⁵) / (a²/³) ==> a⁽⁴/⁵ ⁻²/³) = a⁽²/¹⁵)

This is the simplest way

4 0

3 years ago

Read 2 more answers

3.6x = 5.5, what is it round to the nearest tenth?

Dovator [93]

The answer would be 1.5

6 0

3 years ago

Read 2 more answers

Jennifer is taking a poll for the class elections. So far, she has determined that Kyle will get 52% of the vote, but the margin

Murrr4er [49]

48 <_ v <_<span>56 hope this helps

</span>

7 0

3 years ago

Andrew wants to build a slide for his daughter’s tree house. If the tree house is 5 ft off the ground and he wants the slide to

Lapatulllka [165]

Andrew is wanting to build a slide for his daughter's tree house in the backyard. The tree house is approximately 5 feet off the ground and he wants the slide to have a 30 degree angle with the ground. He will need to by 10 ft of sliding board.

3 0

2 years ago