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Rudiy27
3 years ago
12

Rational Function (x-1)(x+1) (x-2)(x+2)

Mathematics
2 answers:
vladimir2022 [97]3 years ago
4 0
It is a polynomial of degree 4 with zeros at 1, -1, 2, and -2
If multiplied out , the polynomial would be
(x^2 -1)(x^2 - 4)
x^4 - 5x^2 + 4
maria [59]3 years ago
3 0
Yes because everything cancels out
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If f(x) = 4x^2and g(x) = x+1, find (f•g)(x).
vazorg [7]

Answer:

(f.g)(x)=4x^3+4x^2

Step-by-step explanation:

f(x) = 4x^2and g(x) = x+1, (f•g)(x)=?

(f.g)(x)=f(x)*g(x)

(f.g)(x)=4x^2*(x+1)

(f.g)(x)=4x^3+4x^2

hope it helps. .brainliest please

4 0
3 years ago
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HELPPPPPPPPP<br><br> Write the quadratic expression to represent the pattern to the right
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Answer:

  • n^2 + 2n - 1

Step-by-step explanation:

<u>Figure 1</u>

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<u>Figure 2</u>

  • 3*3 - 2

<u>Figure 3</u>

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<u>Equation for nth term</u>

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4 0
3 years ago
A box contains four $1 and six $5 bills. if three bills are selected at random without replacement, find the probability that al
myrzilka [38]

Answer:

C.1/6

Step-by-step explanation:

Initially the box has four $1 and six $5 bills. The probability of selecting a $5 bill in the first trial would be given as;

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= (6)/(4+6) = 3/5

If in the first attempt we actually pick a $5 bill, the number of $5 bills will reduce by one to 5. Now, the probability of picking a $5 bill in the second attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (5)/(4+5) = 5/9

The new number of $5 bills will now be; 6 - 2 = 4 since we have already picked 2 without replacing them.

Now, the probability of picking a $5 bill in the third attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (4)/(4+4) = 1/2

Since the three attempts are independent, the probability of picking  all three $5 bills is;

3/5 * 5/9 * 1/2 = 1/6

7 0
3 years ago
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Alex17521 [72]

Answer:

10 meters

Step-by-step explanation:

6 0
2 years ago
Please help :)
romanna [79]

Answer:

36

Step-by-step explanation:

one calculator price =30/5=6

cost price of 6 calculator=6*6=36

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2 years ago
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