Answer:
The volume of cone v= 113.04 cm³.
Step-by-step explanation:
Formula used to find volume of cone is:
where r is the radius and h is the height of cone.
In the given question we are given:
height h= 6 cm
diameter d= 6 cm
We know radius r = d/2 = 6/2 = 3 cm
so, volume will be:
So, the volume of cone v= 113.04 cm³ given height h= 6cm and radius r= 3cm
The length of AB wit the coordinate (-6, 5) and (8,5). is 14 units
<h3>Distance between two points</h3>
A rectangle is a quadrilateral with 4 sides and angles
Taking the length of AB.
Since AB is slant line, the length of AB will be determined using the distance formula as shown;
D = √(-6-8)² +(5-5)
D = √(-14)²
D = AB = 14 units
Hence the length of AB wit the coordinate (-6, 5) and (8,5). is 14 units
Learn more on distance here: brainly.com/question/1872885
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I think it may be this but you need to round=
7,577.521
Or this one
23,793.41594
I totally forgot how to do this one
vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.
Givens
vi = 160 ft/s
vf = 0 (the rocket stops at the maximum height.)
a = - 9.81 m/s
t = ????
Remark
YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.
Equation
a = (vf - vi)/t
Solve
- 32 = (0 - 160)/t Multiply both sides by t
-32 * t = - 160 Divide by -32
t = - 160/-32
t = 5
You will also need to solve for the height to answer part B
t = 5
vi = 160 m/s
a = - 32
d = ???
d = vi*t + 1/2 a t^2
d = 160*5 + 1/2 * - 32 * 5^2
d = 800 - 400
d = 400 feet
Part B
You are at the maximum height. vi is 0 this time because you are starting to descend.
vi = 0
a = 32 m/s^2
d = 400 feet
t = ??
formula
d = vi*t + 1/2 a t^2
400 = 0 + 1/2 * 32 * t^2
400 = 16 * t^2
400/16 = t^2
t^2 = 25
t = 5 sec
The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.
Answer:
ΔCOG
Step-by-step explanation:
A is reflected in line DB to C.
O is on line DB, so is reflected to itself.
F is reflected in line DB to G.
Hence ΔAOF is reflected in line DB to ΔCOG.
