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meriva
3 years ago
14

HELP PLEASE 75 POINTS PLUS BRAINLIEST

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer: for orange u reverse when u flip for green i answer

-4 < x _< 9

Step-by-step explanation:

Pachacha [2.7K]3 years ago
5 0

Answer:

Answer: ]-4, 9] or (-4, 9]

You reverse the inequality symbol when you multiply by -1

Step-by-step explanation:

-7 < x - 3 < = 6   / +3

-7 + 3 < x - 3 + 3 <= 6 + 3

-4 < x <= 9

Answer: ]-4, 9] or (-4, 9]

You reverse the inequality symbol when you multiply by -1

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For a standard normal distribution (µ=0, σ=1), the area under the curve less than 1.25 is 0.894. What is the approximate percent
Nesterboy [21]

Answer:

10.6%

Step-by-step explanation:

Normal curves are symmetrical.  That means that on a standard normal distribution,  the area less than -1.25 is the same as the area greater than +1.25.  The total area under the curve is 1, so:

P = 1 - 0.894

P = 0.106

Approximately 10.6% of the area under the curve lies below -1.25.

8 0
3 years ago
In the base 5 number system, which number comes after 444,444?
RSB [31]
I think it’s 555,555






3 0
2 years ago
About 5 out of 10 people entering a community college need to take a refresher mathematics course. If there are 970 entering​ st
Ksenya-84 [330]

Answer:

"6 out of 10 people" means the ratio of class:no_class is 6:4

990/10 = 99, the smallest the "class" and the "no_class" add up to is 10. And, generally, the total divides with that nicely, as in this case.

99(6) = 594 ----------- probably class

99(4) = 396 ------------------ probably no class

Total  = 990

I hope this helps

Step-by-step explanation:

BRAINLIEST?

4 0
2 years ago
3x+ (-5y)= 12 what are the values of a,b,&amp; c?
IRISSAK [1]

Answer:

a=3

b=(-5)

c=12

........................

6 0
3 years ago
| x-3 | &lt; x-3<br><br> can someone give a step by step process on how to do this?
statuscvo [17]

Answer:

There are no solutions to the inequality.

Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)  

2. Solve each equation separately

(a) Equation (1)

\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}

(b) Equation (2)

\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &

For example, if x = 0, we get  

|0 - 3| < 0 - 3 or

3 < -3

4 0
3 years ago
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