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Arlecino [84]
3 years ago
11

The 8th term of an AP is 17 & the 19th term is 39, find the 25th term​

Mathematics
2 answers:
seraphim [82]3 years ago
6 0

Answer:

Hi...☺

Here is your answer...✌

GIVEN THAT,

T8 = 17 and T19 = 39

T8 = 17

a + 7d = 17

a = 17 - 7d -----(1)

and

T19 = 39

a + 18d = 39

17 - 7d + 18d = 39 ___ [ from (1) ]

11d = 39-17 = 22

d = 22/11

d = 2

Putting d = 2 in eq(1)

we get

a = 17 - 7(2) = 17 - 14

a = 3

Now,

T25 = a + 24d

= 3 + 24×2 = 3 + 48

= 51

HENCE,

25th term of Given AP is 51

prisoha [69]3 years ago
3 0

Answer:

try multiplication

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?
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Answer:

The correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

Step-by-step explanation:

the given equation is 5y + 4 =(x+3)^{2}  + \frac{1}{2}

Therefore we can write 5y\hspace{0.1cm} = (x+3)^{2} + \frac{1}{2} - 4  \hspace{0.3cm}   \Rightarrow  \hspace{0.2cm}  5y = (x+3)^{2} - \frac{7}{2}   \hspace{0.3cm} \Rightarrow \hspace{0.3cm}  y = \frac{(x+3)^{2}}{5} - \frac{7}{10}

To find the inverse of the above function let us replace x with y and y with x.

Therefore we get

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Now we write the above equation with only y on the Left hand side and we will obtain the inverse of the given function

y = \pm \sqrt{5 (x + \frac{7}{10} )} \hspace{0.1cm} - \hspace{0.1cm} 3 \hspace{0.1cm} \Rightarrow\hspace{0.1cm}  y =  \pm \sqrt{5x + \frac{7}{2} }  - \hspace{0.1cm} 3 \hspace{0.1cm}

Therefore the correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot , y =  \pm \sqrt{5x + \frac{7}{2} }  - \hspace{0.1cm} 3 \hspace{0.1cm}

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3 years ago
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Answer:

Step-by-step explanation:

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6 0
3 years ago
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