The answer is f12 submit 8765
The strategy that Lucy uses to recall her phone number is what is known as Chunking.
<h3>What is Memory?</h3>
This refers to the place where information is stored for future use and can either be a short or long-term memory.
Hence, we can see that based on the breaking down of her phone numbers of Lucy into a particular format that separates them using country/state code, she is making use of chunking.
This method of chunking is effective because it would help Lucy to recall her number quite easily.
Read more about memory here:
brainly.com/question/24688176
#SPJ1
Answer:
x=2√5
Step-by-step explanation:
<u>1st method:</u>
sin(30)=opposite/hypotenuse=√5/x
sin(30)x=√5
x=√5/sin(30)
x=2√5
<u>2nd method:</u>
cos(60)=adjacent/hypotenuse=√5/x
cos(60)x=√5
x=√5/cos(60)
x=2√5
<u>3rd method:</u>
This is a 30-60-90 triangle, so we can multiply the short side, √5, by 2, to get x=2√5
Answer:
y=-2/5x
Step-by-step explanation:
y-y1=m(x-x1)
y-(-2)=-2/5(x-5)
y+2=-2/5(x-5)
y=-2/5x+10/5-2
y=-2/5x+2-2
y=-2/5x
Answer:
(a) 91 employees were absent fewer than six days.
(b) 22 employees were absent more than five days.
(c) 20 employees were absent from 6 up to 12 days.
Step-by-step explanation:
The data for the number of days absent during a calendar year by employees of a manufacturing company is given below.
(a)
The number of employees that were absent for fewer than six days is =
![Frequency\ for\ class\ [0\ - \ 3]+Frequency\ for\ class\ [3\ - \ 6]\\=60 +31\\=91](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B0%5C%20-%20%5C%203%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B3%5C%20-%20%5C%206%5D%5C%5C%3D60%20%2B31%5C%5C%3D91)
Thus, there were 91 employees who were absent for fewer than six days.
(b)
The number of employees that were absent for more than 5 days is =
![Frequency\ for\ class\ [6\ -\ 9]+Frequency\ for\ class\ [9\ -\12]+\\Frequency\ for\ class\ [12\ - \15]\\=14+6+2\\=22](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B6%5C%20-%5C%209%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B9%5C%20-%5C12%5D%2B%5C%5CFrequency%5C%20for%5C%20%20class%5C%20%5B12%5C%20-%20%5C15%5D%5C%5C%3D14%2B6%2B2%5C%5C%3D22)
Thus, there were 22 employees who were absent for more than 5 days.
(c)
The number of employees that were absent from 6 up to 12 days is =
![Frequency\ for\ class\ [6\ -\ 9]+Frequency\ for\ class\ [9\ -\12]=14+6\\=20](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B6%5C%20-%5C%209%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B9%5C%20-%5C12%5D%3D14%2B6%5C%5C%3D20)
Thus, there were 20 employees who were absent from 6 up to 12 days.