Answer:
term of AP = a + (n-1) d
Step-by-step explanation:
Let the first term of arithmetic progression be a and common difference be d.
We have the AP
a , a + d, a+ 2d, a+3d..............................
a + (1-1)d , a + (2-1)d, a + (3-1)d, a + (4-1)d..............................
So if we need term, we can find it as
360 I think
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10rupee notes are 11
20rupee notes are 22
Let 10-rupee note be x
20-rupee note will be x + 11
The equation will be
10x + 20(x + 11) = 550
10x + 20x + 220 = 550
30x = 330
x = 330/30 = 11 = 10rupee notes
y = 11+11 = 22 = 20rupee notes