The answer is Undo I think
Options :
A.) s1 < s2
B.) s1 <= s2
C.) s1.compareTo(s2) == −1
D.) s2.compareTo(s1) < 0
E.) s1.compareTo(s2) < 0
Answer: E.) s1.compareTo(s2) < 0
Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.
If first string = s1 ; second string = s2
To compare s1 with s2, the format is ;
s1.compareTo(s2) ;
If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.
If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.
If both are s1 and s2 are the same, the output will be 0.
Answer:
var birthday = "12/2/1978";
Explanation:
It does not create a date object named birthday because in this statement the birthday is a string which contains 12/2/1978 a date it is not date object it is a string.All other three options are correct way to create a date object.
var birthday = new Date();
creates a date object with the current date and time.
we can also pass date string in the new Date().So var birthday = new Date("12/2/1978"); is also correct.
we can also pass year,month,day in new Date() In this order only.So option fourth is also correct.
Answer:
<h2>The TCP/IP model consists of four layers: application, transport, internet, and network access. Of these four layers, it is the internet layer that is responsible for routing messages.</h2>
