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lakkis [162]
1 year ago
11

What kind of energy transformation occurs when you call someone on a cell phone?

Computers and Technology
1 answer:
andrew11 [14]1 year ago
5 0

The <em><u>sound energy into electric energy and then into radiant energy.</u></em>

<em>[That's it]:)</em>

You might be interested in
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
SVETLANKA909090 [29]

Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
2 years ago
What is the equivalent of film speed in digital cameras?
elena55 [62]
The equivalent of film speed in a digital camera is going to be sensitivity. This will make the correct answer B. 
3 0
3 years ago
Read 2 more answers
What is the importance of using Onedrive in Windows 10 and how knowledge of it will have an impact in today's workplace?
SashulF [63]

The importance of one drive in windows 10 is that it helps the user to synchronize files in their computer.

Onedrive is a cloud storage system that is useful for the storage of files in a secured manner. A person can easily access their files whenever they want to.

In todays workplace a knowledge of onedrive has a great impact because

  • Onedrive offers an unlimited access to files whenever they are needed
  • The files can be available and accessed from anywhere
  • It helps with the organization of files in the work place.

One drive allows for this to be done even when offline. When online, there is an automatic synchronization of the made changes.

Read more at brainly.com/question/17163678?referrer=searchResults

7 0
3 years ago
Read 2 more answers
The code size of 2-address instruction is________________.? 5 bytes? 7 bytes? 3 bytes? 2 bytes
Finger [1]

Answer:

7 bytes

Explanation:

<u>2 Address Instruction</u>

The 2 address instruction consist 3 components in the format.

One is opcode,other two are addresses of destination and source.

<u>Example-</u>

load b,c | Opcode   destination address,source address

add a,d  | Opcode   destination address,source address

sub c,f    | Opcode   destination address,source address

Opcode consists of 1 bytes whereas destination address and source address consist of 3 bytes each.

(1+3+3) bytes=7 bytes

5 0
3 years ago
The cost to ship a package is a flat fee of 75 cents plus 25 cents per pound.
Sonbull [250]

Answer:

The following alterations are done to the program

1. Replace <em>/* Your solution goes here */ </em>with

<em>const int CENTS_PER_POUND = 25;</em>

<em>cout<<"Ship Weight Pounds: "; </em>

<em>cin>>shipWeightPounds; </em>

<em />

2. Include

<em>shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPounds;</em>

after

<em>cout << ", Cents per lb: " << CENTS_PER_POUND;</em>

Explanation:

<em>See attachment for complete program as it should be ordered</em>

<em></em>

This line declares CENTS_PER_POUND as a constant integer and it also initializes the variable to 25

<em>const int CENTS_PER_POUND = 25;</em>

This prompts the user for the weight of the shipping items (in pounds)

<em>cout<<"Ship Weight Pounds: "; </em>

<em />

This gets user input for  the weight of the shipping item

<em>cin>>shipWeightPounds; </em>

<em />

<em>.............................</em>

<em>........</em>

<em>...</em>

This calculates the cost of shipping the item

<em>shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPounds;</em>

Download cpp
6 0
2 years ago
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