<h2>The value of StartFraction 6 Over x EndFraction + 2x2, when x = 3 is 20.</h2>
Explanation:
The given expression is ![\frac{6}{x}+2x^2\\](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7Bx%7D%2B2x%5E2%5C%5C)
When x = 3, the expression becomes ![\frac{6}{3}+2(3)^2](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B3%7D%2B2%283%29%5E2)
![2+2\times9](https://tex.z-dn.net/?f=2%2B2%5Ctimes9)
= 2 + 18 = 20
Answer:
The SQ Root of 493
Step-by-step explanation:
Becaues this triangle is a right triangle, we can find the missing side usiing the pythagorean theorum.
The pythagorean theorun states A^2 + B^2 = C^2, so 18^2 + 13^2= 439
Then all you have to do is find the sq root of 439, but this question askes you not to.
Hope this helps :)
A =(b x h)/2
= 10 x 8
= 80/2
= 40 mm square
The measure of a right angle is 90 degrees