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alexdok [17]
3 years ago
9

Name the property that is shown below.WILL MARK BRAINLIEST

Mathematics
2 answers:
umka2103 [35]3 years ago
5 0

Answer:

  • C. associative property of multiplication

Step-by-step explanation:

Here we see regrouping of the multiplied numbers.

<u>Relevant property is given below</u>

  • The associative property of multiplication:
  • the product of three or more numbers remains the same regardless of how the numbers are grouped.
  • a(bc) = (ab)c
AveGali [126]3 years ago
4 0

Answer:

i think it's the commutative property of Multiplication

Step-by-step explanation:

hope it helps you and if i am correct

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How many times larger is 8*10^6 than 2*10^2
bogdanovich [222]
The first step for solving this question is put both of your given expressions into one and then subtract them. This will look like the following:
8 × 10^{6} - 2 × 10²]
Now to make the calculation easier,, factor the expression.
(8 × 10^{4} - 2) × 10²
Evaluate the power inside the parenthesis.
(8 × 10000 - 2) × 10²
Evaluate the power outside the parenthesis.
(8 × 10000 - 2) × 100
Multiply the numbers inside the parenthesis.
(80000 - 2) × 100
Subtract the numbers in the parenthesis.
79998 × 100
Lastly,, multiply the numbers together to get your final answer.
7999800
This means that 8 × 10^{6} is 7999800 times larger than 2 × 10².
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Step-by-step explanation:

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Can you solve the inequality for: y + 13 &lt; 4
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READ QUESTION CAREFULLY, PLS ANSWER WITH WORKING
kotykmax [81]

Expressions for 'c' and 'd' in terms of 'a' will be (d=4a) and (c=a^2+8).

  In question number 12, it's given that (a+\sqrt{8})^2 can be written as (c+d\sqrt{2}).

So the expression representing the situation will be,

(a+\sqrt{8})^2=(c+d\sqrt{2})

Now simplify the expression,

a^2+8+2a\sqrt{8}=c+d\sqrt{2}

(a^2+8)+2a\sqrt{8}=(c+d\sqrt{2})

(a^2+8)+4a\sqrt{2}=(c+d\sqrt{2})

Compare both the sides of the equation,

c=a^2+8

4a\sqrt{2}=d\sqrt{2}

d=4a

    Therefore, (d=4a) and (c=a^2+8) will be the expressions for c and d in terms of a.

Learn more,

brainly.com/question/13030227

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