Answer: Required mean would be 15.
Step-by-step explanation:
Since we have given that
Number of girls G= 75
Number of boys B= 100
Probability that girls smoke = P₂ = 0.20
Probability that girls don't smoke = P'₂=1-0.20=0.80
Probability that boys smoke = P₁ = 0.30
Probability that boys don't smoke = P'₁=1-0.30=0.70
We need to find the mean of the sampling distribution of the difference in the sample proportion of girl smokers and boys smokers.
So, it becomes,
![E[P_1-P_2]=E[P_1]-E[P_2]\\\\=B\times P_1-G\times P_2\\\\=100\times 0.30-75\times 0.20\\\\=30-15\\\\=15](https://tex.z-dn.net/?f=E%5BP_1-P_2%5D%3DE%5BP_1%5D-E%5BP_2%5D%5C%5C%5C%5C%3DB%5Ctimes%20P_1-G%5Ctimes%20P_2%5C%5C%5C%5C%3D100%5Ctimes%200.30-75%5Ctimes%200.20%5C%5C%5C%5C%3D30-15%5C%5C%5C%5C%3D15)
Hence, required mean would be 15.
7.50
25% also equals 1/4 so divide 130.00 by 4 which equals 32.50
subtract 32.50 from 130.00 which equals the cost, 97.50
97.50 minus 90$ is 7.50, therefore that is the answer
Answer:
Hence - 7 is the answer
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