Meg dilated triangle W by a factor less than 1. Then she performed other transformations that were not dilations to create simil
ar triangle W′.
Which could be the vertices of triangle W?
A. X(–2, 2), Y(–10, 2), Z(–6, 10)
B. X(2, 2), Y(4, 2), Z(3, 4)
C. X(0, 2), Y(4, 2), Z(2, –6)
D. X(2, 2), Y(2, 6), Z(4, 6)
Which could be the vertices of triangle W?
A. X(–2, 2), Y(–10, 2), Z(–6, 10)
B. X(2, 2), Y(4, 2), Z(3, 4)
C. X(0, 2), Y(4, 2), Z(2, –6)
D. X(2, 2), Y(2, 6), Z(4, 6)
1 answer:
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Answer:
492
Step-by-step explanation:
As per the given data of the question:
Total number of students = 2504
Number of students in Java (J) = 1876
Number of students in Linux (L) = 999
Number of students in C = 345
J∩L = 876
L∩C = 231
C∩J = 290
L∩J∩C = 189
Now according to Venn-diagram as drawn below:
Number of students haven taken courses in Java and Linux both only
= J∩L - L∩J∩C
= 876 - 189
= 687
Number of students haven taken courses in Java and C both only
= C∩J - L∩J∩C
= 290 - 189
= 101
Number of students haven taken courses in C and Linux both only
= L∩C - L∩J∩C
= 231 - 189
= 42
Therefore,
Number of students only in Java = 1876 - 687 - 189 - 101 = 899
Number of students only in Linux = 999 - 687 - 189 - 42 = 81
Number of students only in C = 345 - 42 - 189 - 101 = 13
So,
Number of students who have not taken a course in any of these three subjects
= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42
= 492
Hence, the students who have not taken a course in any of these three subjects = 492.
