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grigory [225]
3 years ago
5

Meg dilated triangle W by a factor less than 1. Then she performed other transformations that were not dilations to create simil

ar triangle W′.
Which could be the vertices of triangle W?
A. X(–2, 2), Y(–10, 2), Z(–6, 10)
B. X(2, 2), Y(4, 2), Z(3, 4)
C. X(0, 2), Y(4, 2), Z(2, –6)
D. X(2, 2), Y(2, 6), Z(4, 6)

Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

A. <em>X</em>(–2, 2), <em>Y</em>(–10, 2), <em>Z</em>(–6, 10)

Step-by-step explanation:

This looks a bit tough, but knowing that scale factors less than 1 are ½, ¼, etcetera, I come to this answer, also knowing that in the end, they must have an unproportional relationship.

I hope this is correct, and as always, I am joyous to assist anyone at anytime.

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What is the area of the rhombus shown below?<br>EG = 20<br>FD = 15​
guajiro [1.7K]

To find the area of a rhombus, multiply the two diagonals together then divide by 2.

Area = 20 *15 = 300 / 2 = 150 sq. units.

4 0
3 years ago
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En la primera fase del proceso selectivo para Al cuerpo de profesores eliminan a cuatro novenos De los aspirantes mientras que e
irina1246 [14]

Answer:

The fraction of the applicants who have passed the two phases of the selection process is \frac{10}{63}.

Step-by-step explanation:

The question is:

In the first phase of the selection process for the body of teachers they eliminate four-ninth of the applicants while in the second phase they eliminate 5/7 of those who passed the first phase. If there were 315 applicants what is the fraction of the applicants who have passed the two phases of the selection process?

The total number of applicants is

<em>N</em> = 315.

It is provided that 4/9th of the applicants were eliminated in the first phase.

Then the fraction of candidates who passed the first phase is:

Fraction who passed phase I = 1-\frac{4}{9}=\frac{5}{9}

Now, it is also provided that 5/7 of those who passed the first phase were eliminated in the second phase.

Then the fraction of candidates who passed the second phase is:

Fraction who passed phase II = 1-\frac{5}{7}=\frac{2}{7}

That is, 2/7 of the remaining applicants passed the second phase.

The fraction of the applicants who have passed the two phases is:

\frac{5}{9}\times \frac{2}{7}=\frac{10}{63}

Thus, the fraction of the applicants who have passed the two phases of the selection process is \frac{10}{63}.

8 0
3 years ago
Is √6/8. rational or irrational?
Ipatiy [6.2K]
<h2>Answer:</h2>

<em>The number is </em><u><em>irrational</em></u><em>.</em>

<h2>Step-by-step explanation:</h2>

<h3>1. Convert to decimal.</h3>

\sqrt{\frac{6}{8} } =\sqrt{0.75} =0.8660254038...

<h3>2. Conclude.</h3>

<em>Since this number shows to have infinite decimal figures, it cannot be represented as the ratio of 2 integers. Hence, the number is </em><u><em>irrational</em></u><em>.</em>

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em>Note.</em><em> In case the number expressed in the question was </em>\frac{\sqrt{6} }{8}, the answer  would still be <u><em>irrational</em></u><em>, for the same reasons explained above</em>.

<u><em>-------------------------------------------------------------------------------------------------------</em></u>

<em>Learn more about the classification of numbers here:</em>

<em>brainly.com/question/28292851</em>

<em>brainly.com/question/28292525</em>

<em>brainly.com/question/28281557</em>

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4 0
2 years ago
I need help with this geometry question
Alex17521 [72]

Answer:

x=9; JL= 23

Step-by-step explanation:

To find x:

If JL and KM are equivalent, then JL = KM. Substitute the equations and you get 2x+5 = 7x-40.

Put the similar terms on the same side by subtracting 2x from both sides and adding 40 to both sides. You will get 45=5x.

Get x alone by dividing both sides by 5 and you will get 9=x.

To find JL:

Substitute the x in 2x+5 (JL length equation) with 9. Your new equation will be 2(9) + 5.

2•9 = 18.

18+5=23

8 0
3 years ago
Assume that you have a binomial experiment with p = 0.5 and a sample size of 100.
Shalnov [3]

Answer:

Option D) 50

Step-by-step explanation:

We are given the following information in the question:

p = 0.5

Sample size,n = 100

We have to find the expected value of the distribution.

Formula:

E(X) = np

Putting the values, we get,

E(X) = 100\times 0.5 = 50

The expected value of this distribution is 50.

6 0
4 years ago
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