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grigory [225]
3 years ago
5

Meg dilated triangle W by a factor less than 1. Then she performed other transformations that were not dilations to create simil

ar triangle W′.
Which could be the vertices of triangle W?
A. X(–2, 2), Y(–10, 2), Z(–6, 10)
B. X(2, 2), Y(4, 2), Z(3, 4)
C. X(0, 2), Y(4, 2), Z(2, –6)
D. X(2, 2), Y(2, 6), Z(4, 6)

Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

A. <em>X</em>(–2, 2), <em>Y</em>(–10, 2), <em>Z</em>(–6, 10)

Step-by-step explanation:

This looks a bit tough, but knowing that scale factors less than 1 are ½, ¼, etcetera, I come to this answer, also knowing that in the end, they must have an unproportional relationship.

I hope this is correct, and as always, I am joyous to assist anyone at anytime.

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Change 3/2 to a mixed number
Mariulka [41]
Okay first you have to divide 
2 goes into 3
3/2
2 fits into 3 once
1 and the left over is 1 so
1 1/2

4 0
3 years ago
BRAINLIEST!!!<br> 18. Point p is chosen at random on EH. Find the probability that p is on FG.
shepuryov [24]

Answer:

\frac{2}{5}

Step-by-step explanation:

The total length of this line is 15 units. FG is 6 units long.

This means that the probability of p being on FG would be \frac{6}{15} which can be simplified to \frac{2}{5}

5 0
3 years ago
Read 2 more answers
Na którym rysunku narysowano symetralną odcinka KL?<br>Która z tych liter nie ma osii symetrii?
tensa zangetsu [6.8K]

Answer:

- Only Drawing D has KL being a symmetrical segment.

- Drawings A, B and C have no axis of symmetry.

- Tylko rysunek D ma KL będący segmentem symetrycznym.

- Rysunki A, B i C nie mają osi symetrii.

Step-by-step explanation:

English Translation

In which drawing was the symmetrical segment of KL drawn? Which of these letters has no axis of symmetry?

Solution

The attached image to the question is presented in the attached image to this Solution.

Symmetry is a concept where a figure/shape has half of its part being a mirror image of the other part.

About the line or axis of symmetry, the structure or figure can be rotated at right angles or whole number multiples of right angles and the resulting structure is still the same as the one we started with.

Of the 4 drawings, only drawing D satisfies this conditions/criteria. And Hence, it is the only drawing amongst the four with an axis of symmetry.

In Polish/Po polsku

Załączony obraz do pytania jest przedstawiony na załączonym obrazku do tego rozwiązania.

Symetria to koncepcja, w której figura / kształt ma połowę swojej części stanowiącą odbicie lustrzane drugiej części.

W odniesieniu do linii lub osi symetrii, strukturę lub figurę można obracać pod kątem prostym lub wielokrotności liczby całkowitej pod kątem prostym, a wynikowa struktura jest nadal taka sama jak ta, od której zaczęliśmy.

Z 4 rysunków tylko rysunek D spełnia te warunki / kryteria. I dlatego jest to jedyny rysunek wśród czterech z osią symetrii.

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

3 0
3 years ago
An investment had return of 13% if inflation was 4.1% what was your real return ?
e-lub [12.9K]

Answer: 8.9%

Step-by-step explanation: 13 - 4.1

8 0
2 years ago
A bus travels on an east-west highway connecting two cities A and B that are 100 miles apart. There are 2 services stations alon
melamori03 [73]

Answer:

51/4

Step-by-step explanation:

To begin with you have to understand what is the distribution of the random variable. If X represents the point where the bus breaks down. That is correct.  

X~ Uniform(0,100)

Then the probability mass function is given as follows.

f(x) = P(X=x) = 1/100  \,\,\,\, \text{if} \,\,\,\, 0 \leq x \leq 100\\f(x) = P(X=x) = 0  \,\,\,\, \text{otherwise}

Now, imagine that the D represents the distance from the break down point to the nearest station. Think about this, the first service station is 20 meters away from city A, and the second station is located  70 meters away from city A then the mid point between 20 and 70  is (70+20)/2 = 45 then we can represent D as follows

D(x) =\left\{ \begin{array}{ll}  x  & \mbox{if } 0\leq x \leq 20 \\  x-20 & \mbox{if } 20\leq x < 45\\                70-x & \mbox{if } 45 \leq x \leq 70\\                x-70 & \mbox{if } 70 \leq x \leq 100\\ \end{array}\right.

Now, as we said before X represents the random variable where the bus breaks down, then we form a new random variable Y = D(X), Y is a random variable as well, remember that there is a theorem that says that

E[Y] = E[D(X)] = \int\limits_{-\infty}^{\infty} D(x) f(x) \,\, dx

Where f(x) is the probability mass function of X. Using the information of our problem

E[Y] = \int\limits_{-\infty}^{\infty}  D(x)f(x) dx \\= \frac{1}{100} \bigg[ \int\limits_{0}^{20} x dx +\int\limits_{20}^{45} (x-20) dx +\int\limits_{45}^{70} (70-x) dx +\int\limits_{70}^{100} (x-70) dx  \bigg]\\= \frac{51}{4} = 12.75

3 0
4 years ago
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