He can give at most 2 adult haircuts with the remaining time
<h3>How many adult haircuts at most can he give with the remaining time? </h3>
The inequality is given as:
0.75C + 1.25A <= 7
Also, we have
C = 5
Substitute C = 5 in 0.75C + 1.25A <= 7
0.75 * 5 + 1.25A <= 7
Evaluate the product
3.75 + 1.25A <= 7
Evaluate the like terms
1.25A <= 3.25
Divide by 1.25
A <= 2.6
Rewrite as
A < 3
Hence, he can give at most 2 adult haircuts with the remaining time
Read more about inequalities at:
brainly.com/question/15010638
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<u>Complete question</u>
Horace is a professional hair stylist. Let C represent the number of child haircuts and A represent the number of adult haircuts that Horace can give within 7 hours. 0.75C + 1.25A <= 7
Horace gave 5 child haircuts.
How many adult haircuts at most can he give with the remaining time?
The equation is y = 2/3x + 1
explanation: if you look at 1 on the y axis, you can see the that the line rises by 2, and goes right by 3
Answer:
f(x) = |x|
g(x) = |x| - 2
h(x) = |x| + 3
Step-by-step explanation:
All the functions graphed represent the absolute value functions.
Since function g(x) passes through (0, 0) and (1, 1),
Let the equation of a line passing through these points is,
y = mx + b
Slope of the line passing through these points 'm' = 
m = 1
y-intercept of the line 'b' = 0
Therefore, equation of the line will be,
y = x
And the function representing the two lines (both are the mirror images) joining at the origin will be,
f(x) = |x|
When the parent function is shifted 3 units up, the new function will be
h(x) = |x| + 3
When the parent function is shifted 2 units down,
g(x) = |x| - 2
The answer is actually e although it would have been a
Answer:
- ∠ROK = 36°
- ∠CKO = 96°
- ∠C = 60°
Step-by-step explanation:
The same-side angles at each base are supplementary, so ...
∠ROC = 180° -120° = 60°
Because the trapezoid is isosceles, 60° also the measure of ∠C.
The angle sum theorem tells you ...
∠COK +∠ROK = ∠ROC
24° + ∠ROK = 60°
∠ROK = 36° . . . . . . subtract 24°
__
The sum of angles in ΔCKO is 180°, so ...
∠C +∠COK +∠CKO = 180°
60° +24° +∠CKO = 180°
∠CKO = 96° . . . . . . . . . . . . . subtract 84°
