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nalin [4]
3 years ago
7

(a-3b)^5 expand the binomial please

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0
Expand the binomial:
( a - 3 b ) ^5 =
= a^5 - 5 * a^4 * ( 3 b ) + 10 * a^3 ( 3 b ) ^2 - 10 * a^2 ( 3 b)^3 + 5 *a*( 3 b ) ^4 -
- ( 3 b )^5 =
=  a^5 - 15 a^4 b + 90 a^3 b^2 - 270 a^2 b^3 + 405 a b^4 - 243 b^5
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3 years ago
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Solve for x: 3|x-3| 2=14<br> a. No solution<br> b. x=-1,x=8.3<br> c. x=0,x=7<br> d. x=-1,x=7
VMariaS [17]
I am looking  on the answers, and there is only one case, when a or b or c or d pass:   3|x-3| + 2 = 14.  So I assume, that before two is plus. Then:

3|x-3|+2=14    |minus 2
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From absolute value definition you've got two ways:

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3 0
3 years ago
A lock has four dials. On each dial are the digits 0 to 9 how many possible combinations are there
madam [21]

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7 0
3 years ago
What's the answer to this?
Delicious77 [7]
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4 0
3 years ago
What is the difference between 7/10-44/100
katrin2010 [14]

Answer:

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=26/100

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Step-by-step explanation:

8 0
3 years ago
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