Answer:
-16
Step-by-step explanation:
Follow . PEMDAS
plug the numbers in
4*2 =8 and -4*6=24
add both...
-16.
9514 1404 393
Answer:
R(p) = -3500p^2 +48000p . . . revenue function
$6.86 . . . price for maximum revenue
Step-by-step explanation:
The 2-point form of the equation for a line can be used to find the attendance function.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (27000 -20000)/(6 -8)(x -8) +20000
y = -3500(x -8) +20000
y = 48000 -3500x . . . . y seats sold at price x
The per-game revenue is the product of price and quantity sold. In functional form, this is ...
R(p) = p(48000-3500p)
R(p) = -3500p^2 +48000p . . . per game revenue
__
Revenue is maximized when its derivative is zero.
R'(p) = -7000p +48000
p = 48/7 ≈ 6.86
A ticket price of $6.86 would maximize revenue.
Answer:
Step-by-step explanation:
8a+2b-4 factors into
2(4a+b-2)
The answer would be 9 87/100
Answer:
(a) ![x < \frac{9}{11}](https://tex.z-dn.net/?f=x%20%3C%20%5Cfrac%7B9%7D%7B11%7D)
(b) ![y> 2](https://tex.z-dn.net/?f=y%3E%202)
Step-by-step explanation:
(1):
![x - 15 > 4(-6+3x)](https://tex.z-dn.net/?f=x%20-%2015%20%3E%204%28-6%2B3x%29)
Open bracket
![x - 15 > 4*-6+4*3x](https://tex.z-dn.net/?f=x%20-%2015%20%3E%204%2A-6%2B4%2A3x)
![x - 15 > -24+12x](https://tex.z-dn.net/?f=x%20-%2015%20%3E%20-24%2B12x)
Collect Like terms
![x - 12x > 15 - 24](https://tex.z-dn.net/?f=x%20-%2012x%20%3E%2015%20-%2024)
![-11x > 15- 24](https://tex.z-dn.net/?f=-11x%20%3E%2015-%2024)
![-11x > -9](https://tex.z-dn.net/?f=-11x%20%3E%20-9)
Divide both sides by -11
![x < \frac{-9}{-11}](https://tex.z-dn.net/?f=x%20%3C%20%5Cfrac%7B-9%7D%7B-11%7D)
--- See first attachment for graph
(2):
![6y-7>y+3](https://tex.z-dn.net/?f=6y-7%3Ey%2B3)
Collect Like Terms
![6y-y>7+3](https://tex.z-dn.net/?f=6y-y%3E7%2B3)
![5y > 10](https://tex.z-dn.net/?f=5y%20%3E%2010)
Divide both sides by 5
![y > \frac{10}{5}](https://tex.z-dn.net/?f=y%20%3E%20%5Cfrac%7B10%7D%7B5%7D)
--- See second attachment for graph