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Liono4ka [1.6K]

4 years ago

6

A shop contained some refrigerators and televisions. The total number is 800, and 45% of them were refrigerators. If 60% of refr

igerators were sold and 65% of televisions were sold last week. How many fewer refrigerators were sold than televisions?

1 answer:

dimaraw [331]4 years ago

6 0

Answer:

70

Step-by-step explanation:

The number of refrigerators

$\frac{45}{100} \times 800 = 360$

The number of televisions

$800 - 360 = 440$

The number of refrigerators sold

$\frac{60}{100} \times 360 = 216$

The number of televisions sold

$\frac{65}{100} \times 440 = 286$

How many fewer televisions were sold than television?

$286 - 216 = 70$

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Illusion [34]

The line of the best fit is y = 4.71x—30.31 and at x = 9.5 inches the value of y is 14.5 oz.

<h3>What is the line of best fit?</h3>

A mathematical notion called the line of the best fit connects points spread throughout a graph. It's a type of linear regression that uses scatter data to figure out the best way to define the dots' relationship.

First, we need to find the line of best fit:

Let's suppose the line of the best fit is:

y = mx + c

We can find the value of m:

$\rm m = \dfrac{n\sum xy-\sum x \sum y}{n\sum x^2 - (\sum x)^2}$ and

$\rm c = \dfrac{\sum y -m \sum x}{n}$

After calculating, we will get:

m = 4.71

d = -30.31

y = 4.71x—30.31

Plug x = 9.5

y = 14.43 ≈ 14.5 oz

Thus, the line of the best fit is y = 4.71x—30.31 and at x = 9.5 inches the value of y is 14.5 oz.

Learn more about the line of best fit here:

brainly.com/question/14279419

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2 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

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Nana76 [90]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers