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Nadya [2.5K]
3 years ago
15

Can you guys teach me how to do this??

Mathematics
1 answer:
Vadim26 [7]3 years ago
4 0

The usual margin of error we strive for is a 95% probability that our estimate is within the margin.   Assuming a normal distribution (and that we have a big enough sample not to worry about t tests) that corresponds to between minus and plus two standard deviations of the mean (remember the 68-95-99.7 rule).   So our margin of error is plus or minus two standard deviations.

Answer: ±2%

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\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_4&9\\
a_5&9+d\\
a_6&(9+d)+d\\
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\end{array}\\\\
-------------------------------\\\\
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\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
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d=\textit{common difference}\\
----------\\
n=7\\
d=3
\end{cases}
\\\\\\
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\\\\\\
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