This system of equations has no solution, the 2 lines will never cross
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-11)(-3)) ] / ( 2(-11) )
x = [-5 ± √(25 - (132) ) ] / ( -22 )
x = [-5 ± √(-107) ] / ( -22)
Since we conclude that √-107 is nonreal, the answer to this question is that there are no real solutions.
Answer:
What is the value of x?
<em>x = 40 degrees.</em>
What is the measure of angle AFE?
<em>Angle AFE = 140 degrees</em>
What is the measure of angle BFD?
<em>Angle BFD = 140 degrees.</em>
Step-by-step explanation:
Angle AFC is 90 degrees.
To find angle x, we have to subtract angle BFC.
90 - 50 = 40 degrees.
Line BFE is 180 degrees.
To find angle AFE, we have to subtract angle x from 180 degrees.
We have solved x already.
180 - 40 = 140 degrees.
Angle BFD is just 90 degrees plus 50 degrees.
90 + 50 = 140 degrees.
V = PI x r^2 x H
1348.79 = 3.14 x 5.5^2 x H
1348.79 = 94.985 x h
h = 1348.79 / 94.985
h = 14.2 cm ( round answer if needed)
Rhombus, <span>opposite angles are congruent
One angle is 35 so the opposite angle will be 35 also.
Sum of interior angles in a rhombus equal 360
360 - 35 - 35 = 290
290/2 = 145 (The other two angles will be congruent)
Answer:
The remaining three angles will be 35</span>°<span>, 145</span>°<span>, 145</span>°<span>
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