Charles' weight = Edith's weight + 20% of Edith's weight
We'll use a variable to represent Edith's weight, x.
The decimal form of 20% is 0.2.
60 = x + 0.2x
60 = 1.2x
x = 50
Edith's weight is 50kg.
Hope this helps!
Answer:
12
Step-by-step explanation:
You need to find the least common denominator (LCD) to all the denominators of the fractions present in the equation. These denominators are (writing them in their prime factor form to make our calculations easier):
Therefore, we need to include a factor of 3, and two factors of 2 (
) in our least common denominator, so this LCD will be a perfectly divided by all three given denominators, therefore eliminating all fractions in the equation.
Our LCD is = 
It would be 16 more 6th graders that are not in either band or orchestra.
15 6th Graders in band
9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class
100 6th Graders in total
-42 6th Graders in either class
-------
58 6th Graders in neither class
58-42= 16 more 6th Graders that are not in either class
You're welcome :)
Given:
The scale factor is 1:12.
Dimension of model = 32 cm
To find:
The actual dimension in m.
Solution:
Let x be the actual dimension.
The scale factor is 1:12 and the dimension of model is 32 cm.

On cross multiplication, we get


![[\because 1\ m=100\ cm]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%5C%20m%3D100%5C%20cm%5D)
Therefore, the actual dimension is 3.84 m.