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noname [10]
3 years ago
11

A survey finds that 40% of students ride in a car to school. Eri would like to estimate the probability that if 3 students were

randomly selected, only 1 rides in a car.
To simulate this probability, she lets the numbers 0, 1, 2, and 3 represent a student who rides in a car to school and then 4, 5, 6, 7, 8, and 9 represent a student who does not ride in a car to school. She then has a computer randomly select 3 numbers. She repeats this process for 20 trials.

The results of these trials are shown in the table.
468 380 120 220
553 945 935 607
473 490 074 981
692 518 408 954
943 389 594 569

Based on this simulation, what is the estimated probability that only 1 of 3 randomly selected students rides in a car to school?

Enter your answer, as a decimal, in the box.
Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0
There are twenty numbers in there that are either 0, 1, 2, or 3. There are 125 numbers in total. Your answer is 20/125, or 0.16
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Measure of missing angle
Debora [2.8K]

Answer:

44 degrees.

Step-by-step explanation:

Since angle A is 46 degrees, and angle C is 90 degrees (because of the right angle) you add 46 and 90 (you get 136) then subtract it from 180 (since every triangle equals 180 degrees) which gets you to 44 degrees.

8 0
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Read 2 more answers
10.5 in the form a/b
Lorico [155]
10.5 in the form of a/b = 105/10 = 21/2
4 0
3 years ago
On any given day, the probability that a large local river is polluted by carbon tetrachloride is 0.12. Each day, a test is cond
babymother [125]

Answer:

a) 0.2416

b) 0.4172

c) 0.0253

Step-by-step explanation:

Since the result of the test should be independent of the time , then the that the test number of times that test proves correct is independent of the days the river is correct .

denoting event a A=the test proves correct and B=the river is polluted

a) the test indicates pollution when

- the river is polluted and the test is correct

- the river is not polluted and the test fails

then

P(test indicates pollution)= P(A)*P(B)+ (1-P(A))*(1-P(B)) = 0.12*0.84+0.88*0.16 = 0.2416

b) according to Bayes

P(A∩B)= P(A/B)*P(B) → P(A/B)=P(A∩B)/P(B)

then

P(pollution exists/test indicates pollution)=P(A∩B)/P(B) = 0.84*0.12 / 0.2416 = 0.4172

c) since

P(test indicates no pollution)= P(A)*(1-P(B))+ (1-P(A))*P(B) = 0.84*0.88+  0.16*0.12 = 0.7584

the rate of false positives is

P(river is polluted/test indicates no pollution) = 0.12*0.16 / 0.7584 = 0.0253

4 0
3 years ago
T/0.3 = 1.7/0.9 ( the one I'm pointing at)
Vikentia [17]
I hope this helps you

3 0
3 years ago
9th grade math I don’t understand
harkovskaia [24]
Do you have to keep going or only just one more number it seems to be going by 2’s 4,6,8,10,12 but I’m a little confused since it says it’s 9th grade work
4 0
3 years ago
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