We will assume that we have a function relating between the time and the temperature. Any point in this function can be expressed as (x,y) where x is the time and y is the temperature (any point is expressed as (time, temperature)).
We have two points given:
<span>At 7 p.m. the temperature is 72 degrees F: First point is (7,72)
</span><span>At 10 p.m. the temperature is 52 degrees F: Second point is (10,52)
The rate of change is simply the slope of this function, this slope can be calculated as:
rate of change = (y2-y1) / (x2-x2)
we have y2= 52, y1= 72, x2= 10 and x1= 7
Substituting in the equation, we can calculate the rate of change as follows:
rate of change = (52-72) / (10-7) = -6.667 degrees/hours
Note: The negative sign indicated a DECREASE in the temperature.</span>
To get the distance of the balloon from the the bottom to the ground we apply the following trigonometric formula:
sin θ=opposite/hypotenuse
θ=35°
opposite=height,h
hypotenuse=75ft
Thus plugging our values in the formula we obtain:
sin 35=h/75
solving for h we get
h=75sin 35
h=43.02~43 ft
Answer:
89
Step-by-step explanation:
Because the data is 1-to-multiple
Answer:
a. y = -5x + 4
Step-by-step explanation:
Given the following data;
Slope, m = -5
Intercept, c = 4
Mathematically, the equation of line is given by the formula; y = mx + c
Where;
m is the slope.
x and y are the points
c is the intercept.
Substituting the given parameters, we have;
y = -5x + 4
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
